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AP EAMCET Probability Weightage 2025

AP EAMCET Probability Weightage 2025 is expected to be 3.75% contributing 3- 4 valuable marks in the Mathematics section. Mastering core topics like Conditional Probability, Bayes' Theorem, and Binomial Distribution can significantly elevate your score in AP EAMCET 2025.

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AP EAMCET Probability Weightage 2025 is expected to be 3.75% in the Mathematics section. This chapter holds 3 to 4 marks in the AP EAMCET Mathematics section. These marks can make a significant difference in the overall ranking, as AP EAMCET is highly competitive. The Probability chapter in the AP EAMCET exam covers fundamental concepts such as basic probability concepts, Conditional Probability, Bayes' Theorem, Permutations and Combinations, Independent and Dependent Events, Random Variables and Distributions, and Binomial Probability Distribution. These topics equip students with essential problem-solving skills for analyzing events, calculating probabilities, and understanding probability distributions in various scenarios. In this article, you will be able to understand the AP EAMCET Probability Weightage 2025 along with its concepts that will help you to prepare well for the exam.

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Expected AP EAMCET Probability Weightage 2025

Candidates who are planning to appear for AP EAMCET 2025 must note that the expected AP EAMCET 2025 Probability Weightage is 3.75% of the Mathematics total score. Test takers can expect around 3 to 4 questions from this chapter. Students are advised to master all the topics in the AP EAMCET Probability chapter. 

Check Also:AP EAMCET Syllabus 2025

AP EAMCET Probability Weightage of Previous Years

Here’s a table showing the year-wise weightage of the Probability chapter in AP EAMCET from 2019 to 2024.

Year

Weightage of Probability Chapter (%)

Total Marks (Out of 80)

2019

3.75%

3-4 marks

2020

3.75%3-4 marks

2021

3.75%3-4 marks

2022

3.75%3-4 marks

2023

3.75%3-4 marks

2024

3.75%3-4 marks

The Probability chapter has consistently held a weightage of around 3.75% in the AP EAMCET exam from 2019 to 2024.

Important Topics of AP EAMCET 2025 Probability and Weightage

Here’s a table outlining the important Probability topics for AP EAMCET 2025, along with their expected weightage:

Important Topics in Probability

Significance in AP EAMCET 2025

Expected Weightage (%)

Basic Probability Concepts

Fundamental understanding; frequently asked direct questions.

1% - 2%

Conditional Probability

Key topic; often tested with problems involving dice, cards, or events.

1%

Bayes' Theorem

Advanced concept; occasionally featured in more complex problems.

0.5% - 1%

Permutations and Combinations

Essential for selection-based problems; supports probability calculations.

1%

Independent and Dependent Events

Commonly tested; focuses on determining if events affect each other’s outcome.

0.5% - 1%

Random Variables and Distributions

Related to expected values; requires knowledge of discrete and continuous variables.

0.5% - 1%

Binomial Probability Distribution

Frequently appears in problems involving trials and successes.

0.5% - 1%

Sample Probability Questions for AP EAMCET 2025

Here are some sample questions to illustrate the type of Probability problems you might encounter in AP EAMCET:

Question 1:

A bag contains 4 red balls, 3 blue balls, and 5 green balls. If two balls are drawn randomly, what is the probability that both balls are red?

  • Solution: Total number of balls = 4 + 3 + 5 = 12 Probability of drawing two red balls: P(two red balls)=(42)(122)=666=111P(\text{two red balls}) = \frac{\binom{4}{2}}{\binom{12}{2}} = \frac{6}{66} = \frac{1}{11}P(two red balls)=(212​)(24​)​=666​=111​

Question 2:

A die is thrown twice. What is the probability that the sum of the numbers rolled is 8?

  • Solution: Total possible outcomes = 6 × 6 = 36 Favorable outcomes: (2,6), (3,5), (4,4), (5,3), (6,2) = 5 outcomes. Probability: P(sum is 8)=536P(\text{sum is 8}) = \frac{5}{36}P(sum is 8)=365​

Question 3:

What is the probability of getting at least one head when three coins are tossed?

  • Solution: Total outcomes = 23=82^3 = 823=8 (HHH, HHT, HTH, HTT, THH, THT, TTH, TTT) Probability of no head = 1 outcome (TTT). Probability of at least one head = 1−18=781 - \frac{1}{8} = \frac{7}{8}1−81​=87​.

Question 4: 

What is the probability of getting exactly two heads when three coins are tossed?

  • Solution: Total outcomes = 23=82^3 = 823=8. Outcomes with exactly two heads are (HHT, HTH, and THH), so there are 3 favourable outcomes.
    Probability = 38\frac{3}{8}83​.

Question 5: 

A die is rolled. What is the probability of rolling a number greater than 4?

  • Solution: Possible outcomes greater than 4 are 5 and 6, so there are 2 favorable outcomes out of 6.
    Probability = 26=13\frac{2}{6} = \frac{1}{3}62​=31​.

Question 6: 

A bag contains 5 red balls and 3 blue balls. If one ball is drawn at random, what is the probability it is red?

  • Solution: Total balls = 5 + 3 = 8. Favorable outcomes (red) = 5.
    Probability = 58\frac{5}{8}85​.

Question 7: 

Two dice are rolled together. What is the probability that the sum of the numbers is 7?

  • Solution: Possible outcomes for a sum of 7 are (1,6), (2,5), (3,4), (4,3), (5,2), (6,1), totalling 6 favourable outcomes out of 36.
    Probability = 636=16\frac{6}{36} = \frac{1}{6}366​=61​.

In conclusion, Probability is a high-scoring and important topic in the Mathematics section of AP EAMCET 2025. With an approximate weightage of  3.75%, mastering this topic can significantly boost your overall score. By focusing on understanding the fundamental concepts, practising regularly, and revising frequently, you can ensure that you are well-prepared for the Probability questions in AP EAMCET 2025. 

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