JEE Main 2025 January 29 Mathematics Question Paper with Answer Key Solutions (Available)

Download here the memory-based JEE Main 29 January 2025 Mathematics question paper with answer key solutions for Shift 1 and Shift 2. Mathematics question paper PDFs by top coaching institutes will also be available here.

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JEE Main 2025 January 29 Mathematics Question Paper with Answer Key Solutions (Available)

JEE Main 29 January 2025 Mathematics Question Paper: Candidates who took the JEE Main 2025 Mathematics exam on January 29, 2025, can now access the memory-based question paper along with answer key solutions for both Shift 1 and Shift 2. This valuable resource allows students to evaluate their performance, identify areas for improvement, and refine their strategies for future attempts.  The memory-based question paper, complete with answer key solutions, is available in PDF format, making it easy for students to access and review. Additionally, well-known coaching institutes will provide their own Mathematics question paper PDFs, offering students a comprehensive analysis of the exam and expert insights into the solutions.

JEE Main 29 January 2025 Mathematics Shift 1 Question Paper with Answer Key Solutions

Here is JEE Main 29 January 2025 Mathematics question paper with answer key solutions for Shift 1: 

Q.No.QuestionsAnswers
1The minimum value of n for which the number of integer terms in the binomial expansion of (71/3 + 111/2) is 183, is2184
2lim (n→0) ∑ (k = 1 to n) [(k3 + 6k2 + 11k +5)/(k + 3)! = ?5/3
3Sum of first three terms of an AP with integral common difference is 54 and sum of first twenty terms lies between 1600 to 1800, find a11.90
4Area enclosed by y ≥ |x - 1|, y + |x| ≤ 3, x2 ≤ 2y - 3 is A, then 6A is (in sq. units)10
5Find I = 80 0π/2 [(sinx + cosx) / (9sinx + 16cosx)]dx(80/337) [(25π/2) + 7 ln(9/16)]
6If R be a relation defined on (0, π/2) such that xRy sec2x - tan2y = 1, then the relation R isReflexive and transitive only
7Number of 7 digit numbers made with the digits 1, 2, 3 such that sum of the digits is 11 is equal to16!
8If z1 lies on | z - 8 + 2i | = 1 and z2 lies on | z - 2 - 6i | = 2, then | z- z2 |min is (where i = √-1)7
9If cos-1x = π + sin-1x + sin-1(2x - 1), then find the sum of all values of x.0
10Find the minimum value of p such that 
lim (x→0) { x ([1/x] + [2/x] + ... + [p/x]) - x2 ([1/x2] + [2/x2] + ... + [9/x2]) }
24

JEE Main 29 January 2025 Mathematics Shift 2 Question Paper with Answer Key Solutions

Here is JEE Main 29 January 2025 Mathematics question paper with answer key solutions for Shift 2: 

Q.No.QuestionsAnswers
1If the letters of the word "KANPUR" are arranged in dictionary, then the 440th word isPRKAUN
2If 3107 is divided by 23, then remainder is6
3Let aij = (√2)i+j, A = [aij]3x3 If sum of third row of A2 is α + β√2, then α + βis224
4Let f(x) = 0x t(t2 - 3t + 20) dt, x ∈ (1, 3) and range of f(x) is (α, β), then α + β is equal to185/2
5lim (x→0) [ cosecx ((2cos2x + 3cosx)1/2 - (cos2x + sinx + 4)1/2 ] = ?-1/2√5
6Let the line L be (x - 1)/1 = (y - 4)/3 = (z - 7)/5 = λ and foot of perpendicular from (1, -2, -1) to L is (α, β, γ), then find the value of α + β + γ.-102/35
7If the exhaustive values of a for which the equation 2x2 + (a - 5)x + 15 = 3a has no real roots is (α, β), then 14(α + β) | is equal to56
8Area enclosed between the curves |y| = 1 - x2 and x2 + y2 = 1 is (π - α) sq. units, then 9α is24
9If log y = x log (2/5), x ∈ ℕ ∪ {0}. Then sum of all values of y equals to5/3
10There is an arithmetic progression a1, a2, a3, ... a2024 and a1 + (a5 + a10 + a15 - a2020) + a2024 = 2233. Find the value of a1 + a2 + a3 + ... a2024.11132
11Two points (4, 2) and (0, 2) lie on the circle whose centre lies on 3x + 2y + 2 = 0 then the length of the chord whose mid-point is (1, 2), is2√3

JEE Main 29 January 2025 Mathematics Question Paper PDF Download

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JEE Main 29 January 2025 Mathematics Question Paper PDFs by Coaching Institutions

For both Shift 1 and Shift 2, JEE Main 29 January 2025 Mathematics answer key and question paper PDF links have been provided as released by Resonance, Aakash, and Vedantu in the below table:

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