GATE 2024 ECE Daily Practice Questions for 1 September 2023

Chinmayai Bobade

Updated On: September 01, 2023 06:29 PM

Here are GATE 2024 ECE Daily Practice Questions for 1 September 2023. Solve these questions and enhance your Electronics and Communication Engineering preparation!
GATE 2024 ECE Daily Practice Questions for 1 September 2023GATE 2024 ECE Daily Practice Questions for 1 September 2023

GATE 2024 ECE Daily Practice Questions for 1 September 2023: One of the best ways to prepare for GATE 2024 is to maintain consistency and develop a habit of solving practice questions daily. For September 1, 2023, GATE ECE 2024 daily practice questions are outlined below. These questions are taken from past question papers and hence, they will be very useful for preparation and may also be repeated this year.

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GATE 2024 ECE Daily Practice Questions for 1 September 2023

Find GATE 2024 daily practice questions for Electronics and Communication Engineering here. Solve them to analyze your exam preparation.

Question 1: The average power delivered to an impedance (4 - j3) ohms by a current 5 cos(100pt + 100 ) A is
(A) 44.2 W
(B) 50 W
(C) 62.5 W
(D) 125 W
Question 2: A source alphabet consists of N symbols with the probability of the first two symbols being the same. A source encoder increases the probability of the first symbol by a small amount ε (epsilon) and decreases that of the second by ε. After encoding, the entropy of the source
(A) increases
(B) remains the same
(C) increases only if N = 2
(D) decreases
Question 3: Two independent random variables X and Y are uniformly distributed in the interval [–1, 1]. The probability that max[X, Y] is less than 21 is
(A) 4/3
(B) 9/16
(C) 1/4
(D) 2/3
Question 4: A transmission line with a characteristic impedance of 100 W is used to match a 50 W section to a 200 W section. If the matching is to be done both at 429 MHz and 1 GHz, the length of the transmission line can be approximately
(A) 82.5 cm
(B) 1.05 m
(C) 1.58 m
(D) 1.75 m
Question 5: A binary symmetric channel (BSC) has a transition probability of 1/8. If the binary transmit symbol X is such that P(X=0) = 9/10, then the probability of error for an optimum receiver will be
(A) 7/80
(B) 63/80
(C) 9/10
(D) 1/10

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