COMEDK UGET 2025 Optics Practice Questions with Solutions: Optics is one of the most important topics of the COMEDK UGET 2025 Physics syllabus carrying around 25-26% weightage. The Optics topic is divided into two parts, namely Ray Topics and Wave Topics. To prepare Optics for COMEDK UGET 2025 you must study it thoroughly and practise various questions to gain expertise in this section. For that purpose, we have added COMEDK UGET 2025 Optics practice questions with solutions on this page. The COMEDK sample questions for Optics have been taken from the previous year's papers. Attempt these important questions from COMEDK Optic chapter to find out your understanding of the topic and work on your mistakes. 

According to the COMEDK previous year paper, Ray Optics and Wave Optics combined carry approximately 26% weightage, and will have a total number of 16 questions asked from them. Since Optics is a high-weightage topic of the COMEDK UGET 2025 syllabus PDF, you must practice various questions from this topic. COMEDK UGET 2025 exam will be held on May 10, 2025. Get access to COMEDK Optics important questions 2025 here. 

Also Check - COMEDK Chapter Wise PYQ for Mathematics

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COMEDK UGET 2025 Optics Important Topics

COMEDK UGET 2025 Physics syllabus is prepared according to the CBSE Class 11 and 12 syllabus. Optics is an important topic of the COMEDK Physics syllabus and includes various sub-topics. You can check the detailed COMEDK UGET 2025 Optics sub-topics below. 

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COMEDK UGET 2025 Optics Expected Weightage

The COMEDK UGET optics weightage will help you know the number of questions that are expected to be asked. As per the previous year's paper analysis, Optics weightage for COMEDK UGET has been given below. Around 8 questions are expected from Ray Optics and 8 from Wave topics. A total of 16 questions will be asked from the Optic topic of the COMEDK UGET Physics syllabus. 

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COMEDK UGET 2025 Optics Practice Questions with Solutions

We have mentioned the COMEDK UGET 2025 Optics sample questions with solution below. Attempt the following COMEDK Optics practice questions and analyze your exam preparation. If you got any answer wrong, go through that topic again and improve your shortcomings. 

 The calculations in Optic can be lengthy therefore while solving the questions analyze your speed and if you lack them improve your time management skills, restudy the forumale you are forgetting, and go through the concepts again. 

COMEDK UGET Optics Important Questions

Q1- When a particular wavelength of light is used the focal length of a convex mirror is found to be  10 cm. If the wavelength of the incident light is doubled keeping the area of the mirror constant, the focal length of the mirror will be:

A) 5 cm

B) 20 cm

C) 15 cm

D) 10 cm

Correct Answer: Option D

Explanation: A convex mirror's focal length is not affected by the wavelength of the incident light. This is because the curvature of a mirror's reflecting surface determines its focal length rather than the qualities of the light employed.

As a result, even if the wavelength of the incident light doubles, the mirror's focal length remains constant. The convex mirror's initial focal length is. So, even if the wavelength is doubled, the focal length remains: 10 cm

Q2- A hollow prism is filled with water and placed in air. It will deviate the incident rays

A) Towards or away from the base

B) Away from the base

C) Parallel to the base

D) Towards the base

Correct Answer: Option D

Explanation: To estimate how a hollow prism filled with water will affect the deviation of incident rays in air, we must examine the principles of refraction as well as the prism's shape.

When light passes through a prism, it refracts, which is the bending of light caused by a change in speed as it moves from one medium to another. For a particular material, the amount of bending is determined by its refractive index and the angle at which light enters it.

A hollow prism filled with water has faces composed of a substance that does not have the same refractive index as water. When the prism is placed in the air, the light will be refracted twice: once when it enters the water and again when it emerges. The bending effect is caused by the difference in refractive indices between air and water.

Typically, water has a greater refractive index than air. This means that when light enters the water from the air, it bends toward the normal, but when it escapes, it bends away from the normal. The overall path of the incident light through the prism causes a divergence towards the prism's base.

The correct solution, based on the principles of refraction and the geometry of the prism, is the correct answer is Option D.

Q3- A person has a normal near point  25 cm. What is the magnifying power of the simple microscope he used, if the focal length of the convex lens used is 10 cm and the final image is formed at the least distance of distinct vision?

A) 7

B) 3.5

C) 25

D) 2.5

Correct Answer: Option C

Explanation:

The magnifying power (MP) of a simple microscope when the final image is formed at the least distance of distinct vision (which is general taken as 25 CM or D) can be calculated using the formulae:

MP= 1+ D divide by f

Where:

D is the least distance of distinct vision (25 cm in this case) and

f is the focal length of the convex lens used in the simple microscope.

Given in the question f= 10 cm Substitutings the given values into the formula gives:

MP= 1+ 25 divide by 10= 1+2.5= 5.5

Hence the magnifying power of the simple microscope is 3.5

Q4- Two converging lenses of focal lengths 20 cm and 40 cm are placed in contact. The effective power of the combination is

A) 5.25 D

B) 7.25 D

C) 2.75 D

D) 7.5 D

Correct Answer:Option D

Explanation:

Given f₁ = 20 cm, f₂ = 40 cm

Since, power P = _{1 divide by f} = P₁= _{1 divide by} f₁ = 100 divide by 20 = 5 D

and P_{2 = 1 divide by} F_{2 =} 100 divide by 40 = 2.5 D

Effective power, P = P₁₊ P₂ = 5 + 2.5 = 7.5D

Q5- The magnifying power of a telescope is 9. When it is adjusted for parallel rays, the distance between the objective and eyepiece is 20 cm. The focal length of lenses are

A) 10 cm, 10 cm

B) 15 cm, 5 cm

C) 18 cm, 2 cm

D) 11 cm, 9 cm

Correct Answer: Option C

Explanation:

Given M = f_{0 divide by} f_e = 9 ~f₀ = 9f_e

Also f₀ + f_e = 20

~9 f_e + f_e  = 20 ~ f_e = 2 cm

Therefore, f₀ = 9*2= 18 cm

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