JEE Main Chemistry 2025 Predicted Topics and Questions

JEE Main Chemistry 2025 Predicted Topics and Questions have been provided here. As the JEE Main 2025 Session 2 Exam is started, candidates looking for a comprehensive study on the predicted topics and questions of JEE Main 2025 Chemistry can find it here. The JEE Main Chemistry Syllabus can be divided into Physical Chemistry, Inorganic Chemistry, and Organic Chemistry. The predicted JEE Main Chemistry Weightage 2025 is 30% for Inorganic and Physical Chemistry and 35% for Organic Chemistry. Transition Elements & Coordination Compounds, Periodic Table, s and p-Block Elements are topics expected with a weightage of 9.9% which is approximately 3 questions from each topic. JEE Main Chemistry 2025 predicted topics and questions are based on previous trends and expert analysis.

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The JEE Main Chemistry Important Topics 2025 from Physical Chemistry include the Mole Concept, Atomic Structure, Chemical Thermodynamics, Chemical Bonding and Molecular Structure, and d- and f-Block Elements from Inorganic Chemistry. From Organic Chemistry, focusing more on Organic Compounds Containing Oxygen, Biomolecules, General Organic Chemistry (GOC). As the JEE Main 2025 Last Minute Preparation Tips , candidates should practice JEE Main Previous Year Question Papers with Solutions and revise the important topics as mentioned here. Check JEE Mains Chemistry Predicted Questions and Topics are here.

Check: JEE Main Chemistry Formulas 2025

JEE Main Chemistry 2025 Predicted Questions (Unsolved)

JEE Main 2025 Session 2 Exam is conducted from April 2, 3, 4, 7, and 8, 2025, for Paper 1 (B.Tech) and April 9, 2025, for B.Arch and B.Plan. Candidates can check the unsolved JEE Main Chemistry 2025 Predicted Questions here. However, we have also provided some solved questions below for better understanding and clarification.

Physical Chemistry Predicted Topics and Questions

Given below are some of the Physical Chemistry Predicted Questions here.

In Organic Chemistry Predicted Topics and Questions

Check out the Organic Chemistry Predicated topics and questions here

Organic Chemistry Predicted Topics and Questions

JEE Main Chemistry 2025 Predicted Topics

JEE Mains Chemistry Weightage 2025 (Predicted)

The predicted JEE Mains Chemistry Weightage 2025 has been provided in the following table.

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JEE Main Chemistry 2025 Predicted Questions (Solved)

Physical Chemistry: Mole Concept

• Question:
  • Calculate the molarity of a solution prepared by dissolving 11.7 g of NaCl in 200 mL of water.
• Solution:
  • Calculate the molar mass of NaCl:
  • Na = 23 g/mol, Cl = 35.5 g/mol
  • Molar mass of NaCl = 23 + 35.5 = 58.5 g/mole
  • Calculate the number of moles of NaCl:
  • Moles = Mass / Molar mass
  • Moles = 11.7 g / 58.5 g/mol = 0.2 mol
  • Convert the volume of water to liters:
  • 200 mL = 200 / 1000 = 0.2 L
  • Calculate the molarity:
  • Molarity (M) = Moles of solute / Liters of solution
  • M = 0.2 mol / 0.2 L = 1 M
  • Answer: The molarity of the solution is 1 M.

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2. Inorganic Chemistry: Chemical Bonding

• Question:
  • Predict the shape and hybridization of the central atom in an SF6​ molecule.
• Solution:
  • Determine the number of electron pairs:
  • S has 6 valence electrons.
  • Each F contributes 1 valence electron.
  • Total valence electrons = 6 + (6 x 1) = 12
  • Total electron pairs = 12 / 2 = 6
  • Determine the hybridization:
  • 6 electron pairs correspond to sp3d2 hybridization.
  • Determine the shape:
  • sp3d2 hybridization with 6 bonding pairs and 0 lone pairs results in an octahedral shape.
  • Answer: The shape of SF6​ is octahedral, and the hybridization of the sulfur atom is sp3d2.

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3. Organic Chemistry: General Organic Chemistry (GOC)

• Question:
  • Arrange the following carbocations in order of increasing stability:
    • (CH3​)3​C+, (CH3​)2​CH+, CH3​CH2+​.
• Solution:
  • Understand carbocation stability:
  • Carbocation stability increases with the number of alkyl groups attached to the positively charged carbon due to hyperconjugation and inductive effects.
  • Apply the concept:
  • (CH ₃ ​)3​C+ (tertiary) has the most alkyl groups, making it the most stable.
  • (CH ₃ ​)2​CH+ (secondary) is next.
  • CH ₃ ​CH2+​ (primary) is the least stable.
  • Answer: The order of increasing stability is: CH ₃ ​CH ₂ +​<(CH _3​ )2​CH+<(CH ₃ ​)3​C+.

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4. Electrochemistry:

• Question:
  • Calculate the standard cell potential (E°cell) for the following reaction:
    • Zn(s)+Cu ₂ +(aq)→Zn ₂ +(aq)+Cu(s)
    • Given: E°(Cu ₂ +/Cu)=+0.34V and E°(Zn ₂ +/Zn)=−0.76V.
• Solution:
  • Identify the oxidation and reduction half-reactions:
  • Oxidation: Zn(s)→Zn ₂ +(aq)+2e−
  • Reduction: Cu2+(aq)+2e−→Cu(s)
  • Apply the formula:
  • E°cell=E°(cathode)−E°(anode)
  • E°cell=E°(Cu ₂ +/Cu)−E°(Zn ₂ +/Zn)
  • E°cell=0.34V−(−0.76V)=1.10V
  • Answer: The standard cell potential is 1.10 V.

Check:

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5. Chemical Kinetics:

• Question:
  • The rate constant for a first-order reaction is 2.3×10−3s−1. How long will it take for the reactant concentration to decrease to 10% of its initial value?
• Solution:
  • Use the integrated rate law for a first-order reaction:
  • ln(At​/A0​)=−kt
  • Where:
    • At​ = concentration at time t
    • A0​ = initial concentration
    • k = rate constant
    • t = time 1
  • Substitute the given values:
  • At​=0.1A0​ (10% of initial)
  • ln(0.1A0​/A0​)=−(2.3×10−3s−1)t
  • ln(0.1)=−(2.3×10−3s−1)t
  • Solve for t:
  • −2.303=−(2.3×10−3s−1)t
  • t=2.303/(2.3×10−3s−1)=1001.3s
• Answer: It will take approximately 1001.3 seconds.

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6. Solid State:

• Question:
  • A metal crystallizes in a face-centred cubic (FCC) lattice. If the edge length of the unit cell is 400 pm, calculate the radius of the metal atom.
• Solution:
  • Relationship between edge length (a) and radius (r) in an FCC lattice:
  • 
  • Substitute the given edge length:
  • 
  • Solve for r:
  • 
  • Answer: The radius of the metal atom is 141.4 pm.

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7. p-Block Elements:

• Question:
  • Explain the trend in the acidic strength of the oxoacids of chlorine: HClO, HClO₂, HClO₃, and HClO₄.
• Solution:
  • Oxidation state:
  • The acidic strength of oxoacids increases with the oxidation state of the central atom.
  • Explanation:
  • As the oxidation state of chlorine increases, the ability of the chlorine atom to withdraw electron density from the oxygen-hydrogen bond increases. This weakens the O-H bond, making it easier to release a proton (H+), thus increasing acidic strength.
  • Trend:
  • HClO < HClO₂ < HClO₃ < HClO₄
  • Answer: The acidic strength increases with an increasing oxidation state of chlorine.

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8. Coordination Compounds:

• Question:
  • Write the IUPAC name of the complex: [Co(NH _³ ​)4​Cl ₂ ​]Cl.
• Solution:
  • Identify the ligands and central metal atom:
  • Ligands: 4 ammine (NH₃), 2 chloro (Cl)
  • Central metal: Cobalt (Co)
  • Determine the oxidation state of the central metal:
  • Let the oxidation state of Co be x.
  • x + (4 x 0) + (2 x -1) + (-1) = 0
  • x - 3 = 0
  • x = +3
  • Write the IUPAC name:
  • Tetraammine dichlorocobalt(III) chloride
  • Answer: Tetraamminedichlorocobalt(III) chloride.

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9. Organic Chemistry: Hydrocarbons:

• Question:
  • Write the major product of the reaction of propene with HBr in the presence of peroxide.
• Solution:
  • Anti-Markovnikov's rule:
  • In the presence of peroxide, HBr adds to alkenes according to the anti-Markovnikov's rule, where the bromine atom adds to the less substituted carbon.
  • Apply the rule to propene:
  • 
  • Answer: 1-bromopropane.

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10. Biomolecules:

• Question:
  • What are essential amino acids? Give two examples.
• Solution:
  • Definition:
  • Essential amino acids are those that cannot be synthesized by the human body and must be obtained from the diet.
  • Examples:
  • Valine
  • Leucine.
  • Answer: Essential amino acids are amino acids that the human body cannot synthesize. Examples are valine and leucine.

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