WBJEE 2025 Physical Chemistry Practice Questions with Solutions

Prateek Lakhera

Updated On: January 29, 2025 10:01 AM | WBJEE

WBJEE 2025 Physical Chemistry practice questions with solutions have been provided here to boost your exam preparation and help you score the maximum marks. The WBJEE Physical Chemistry sample questions include topics such as Atomic Structure, Radioactivity and Nuclear Chemistry etc. 
WBJEE 2025 Physical Chemistry Practice Questions with Solutions

WBJEE 2025 Physical Chemistry Practice Questions with Solutions: Physical Chemistry covers a significant section of the WBJEE 2025 Chemistry syllabus PDF . The WBJEE 2025 Physical Chemistry practice questions comprise some of the important topics, such as Atomic Structure, Redox Reactions, Gaseous States, Thermodynamics etc. With an approximate weightage of 4-7% in the WBJEE 2025 exam the question paper will cover 8-9 questions from this chapter. However, since the topics are already covered in the West Bengal 11th and 12th standard Board exam curriculum, you are advsied to focus on solving WBJEE 2025 Physical Chemistry practice questions rather than spending time studying all the topics from scratch. Attempting as many WBJEE Physical Chemistry sample questions as you can will make you familiar with the frequently asked and most expected questions in the upcoming examination. In this article, we will discuss a series of practice questions for WBJEE 2025 Physical Chemistry chapter in detail. We will also provide you with some of the most important WBJEE 2025 Physical Chemistry practice questions with solutions based on the past years' paper review and format.

Also Check - WBJEE 2025 Properties of Matter Practice Questions with Solutions

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List of WBJEE 2025 Physical Chemistry Sub Topics for Exam Preparations

While solving WBJEE Physical Chemistry sample questions you may come across a number of topics and sub topics that are repetitive and asked more often. These are the sub topics that you need to pay attention to since the majority of the questions will be based around these. In this section we have listed the key sub topics from the Physical Chemistry chapter as mentioned in the WBJEE 2025 syllabus PDF .

Chapter Sub Topics

Physical Chemistry

Atoms, Molecules, and Chemical Arithmetic

Atomic Structure

Radioactivity and Nuclear Chemistry

Solid State

Liquid State

Gaseous State

Chemical Energetics and Chemical Dynamics

Chemical Energetics

Chemical Equilibria

Chemical Dynamics

Order and molecularity

Physical Chemistry of Solutions

Ionic and Redox Equilibria

Redox Equilibria

Also Check - WBJEE 2025 Chemistry Topic-Wise Weightage & List of Important Topics

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WBJEE 2025 Physical Chemistry Expected Weightage

While practising with WBJEE Physical Chemistry sample questions you should also be aware of the expected marks weightage and the probable number of questions in the upcoming examination. By analyzing the marks weightage you can figure out which topics to prioritize and accordingly solve WBJEE 2025 Physical Chemistry practice questions from those sub topics. If you manage to attempt 5-6 questions from the chapter, you can score at least 10-12 marks. Let’s have a look at the tentative WBJEE 2025 marks weightage for Physical Chemistry below.

Topic

Expected Number of Questions

Expected Weightage

Physical Chemistry

8-9

4-7%

WBJEE 2025 Physical Chemistry Practice Questions with Solutions

Practising regularly with WBJEE Physical Chemistry sample questions can make all the difference in your exam preparations. By attempting WBJEE 2025 Physical Chemistry practice questions with solutions, you can get a glimpse of the probable questions, correct asnwer and the step-by-step solution to each question. Check out some of the important WBJEE 2025 Physical Chemistry practice questions picked from the past years' exam papers by experts.

Q1. Arrange the following in order of increasing mass:-

I. 1 mole of N 2

II. 0.5 mole of O 3

III. 3.011 x 10 23 molecules of O 2

IV. 0.5 gm atom of O 2

a. IV < III < II < I

b. IV < I < III < II

c. III < II < IV < I

d. I < III < II < IV

Ans: a. IV < III < II < I

Q2. 63 g of a compound (Mol. Wt. = 126) was dissolved in 500 g distilled water. The density of the resultant solution as 1.126 g/ml. The molarity of the solution is:

a. 1.25 M

b. 1.0 M

c. 0.75 M

d. 1.1 M

Ans: b. 1.0 M

Solution:

Given

Mass of compound (Solute) = 63g

Mass of solvent = 500g

Molecular weight = 126g

Density = 1.126g/mL

Molarity =?

Mass of solution = Mass of solute + Mass of solvent

= 63 + 500 = 563g

Number of moles = 63/126 = 0.5 moles

Volume= Mass/Density = 563/1.126 mL

Now, using the formula of molarity,

M = number of moles of solute/volume of solution

1 = (0.5 x 1000)/(563/1.126)

1= 1.126 x 1000 x 0.5/563 = 1 Molar or 1.0M

Q3. How much solid oxalic acid (Molecular weight 126) has to be weighed to prepare 100 ml. exactly 0.1 (N) oxalic acid solution in water?

a. 1.26 g

b. 0.126 g

c. 0.63 g

d. 0.063 g

Ans: c. 0.63 g

Solution:

Given, the molecular weight of oxalic acid = 126

Volume = 100 mL

Normality = 0.1 N

Mass =?

We know,

Normality = (Mass/equivalent weight)/Volume

Equivalent weight= Molecular weight/η-factor = 126/2 [η-factor = 2 for oxalic acid]

0.1 = Mass/(63x100/1000) = Mass = 0.1 x 63 x 100/1000

Mass = 0.63 g

Q4. Consider an electron moving in the first Bohr orbit of a Hw + ion with a velocity v 1 . If it is allowed to move in the third Bohr orbit with a velocity v 3 , then indicate the correct v 3 :v 1 ratio.

a. 3:1

b. 2:1

c. 1:3

d. 1:2

Ans: c. 1:3

Solution: In the Bohr model, the velocity of an electron in an orbit is inversely proportional to the radius of that orbit for a given atom or ion. Specifically, the velocity v of an electron in the nth orbit of a hydrogen-like atom (or ion) is given by:

v n = k/n

Where k is a constant for a particular atom/ion and n is the principal quantum number of the orbit (1 for the first orbit, 2 for the second, etc.).

From this relationship, it follows that the velocity of the electron decreases as the principal quantum number increases. Specifically, for the electron in the first Bohr orbit (n = 1) and the third Bohr orbit (n = 3) of the He + ion, the velocities v 1 and v 3 would be directly related by the ratio of their orbit numbers.

Thus: v 3 /v 1 = (k/3)/(k/1) = 1/3

Therefore, the velocity ratio v 3 :v 1 is 1:3 This indicates that the electron in the third orbit moves at one-third the velocity of the electron in the first orbit.

Q5. Which hydrogen-like species will have the same radius as that of the 1 st Bohr orbit of the hydrogen atom?

a. n = 2, Li 2+

b. n = 2, Be 3+

c. n= 2, He +

d. n =3, Li 2+

Ans: b. n = 2, Be 3+

Q6. The number of unpaired electrons in Mn 2+ ion is:

a. 2

b. 3

c. 5

d. 6

Ans: c. 5

Solution:

The atomic number of Mn is 25.

Electronic configuration of Mn = [Ar]3d 5 4s 2

Electronic configuration of Mn 2+ = [Ar]3d 5

There are five 3d orbitals, each orbital occupied by a single electron. Thus, number of unpaired electrons is 5.

Mn 2+ = [Ar]3d 5

Q7. The equivalent weight of Na2S2O3 (Gram molecular weight = M) in the given reaction I 2 + 2Na 2 S 2 O 3 = 2NaI + Na 2 S 4 O 6 is:

a. M/2

b. M

c. 2M

d. M/4

Ans: b. M

Solution:

The equivalent weight of a substance is the weight of the substance that reacts with or is equivalent to one mole of hydrogen ions or one mole of electrons. In this reaction, the oxidation state of sulfur in Na 2 S 2 O 3 is +2, while in Na 2 S 4 O 6 it is +2.5 This means that each sulfur atom in Na 2 S 2 O 3 loses 0.5 electrons. Since there are two sulfur atoms per molecule of Na 2 S 2 O 3 , the total number of electrons lost per molecule is 1. Therefore, the equivalent weight of Na 2 S 2 O 3 is equal to its molecular weight divided by the number of electrons lost per molecule, which is M/1 or simply M.

Q8. The compressibility factor for a van der Waal gas at high pressure is:

a. 1 + RT/Pb

b. 1+ Pb/RT

c. 1 - Pb/RT

d. 1

Ans: b. 1+ Pb/RT

Q9. For a first-order reaction with a rate constant k, the slope of the plot of log (reactant concentration) against time is:

a. k/2.303

b. k

c. -k/2.303

d. -k

Ans: c. -k/2.303

Q10. A solution containing 4g of polymer in a 4.0-litre solution at 27°C shows an osmotic pressure of 3.0 x 10 -4 atm. The molar mass of the polymer in g/mol is:

a. 820000

b. 82000

c. 8200

d. 820

Ans: b. 82000

Quick Links: To further improve your overall preparation and chances of scoring 45+ in the Chemistry paper (Paper II), you should solve WBJEE 2025 mock test from the Physical Chemistry chapter. This will help you assess your progress and exam readiness, as well as boost your confidence and time management skills. A combination of WBJEE 2025 Physical Chemistry practice questions with solutions and mock test series is the key to success.

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We hope that this post on the WBJEE 2025 Physical Chemistry Practice Questions with Solutions was helpful and informative. For the latest exam updates, stay tuned to CollegeDekho!

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FAQs

How many practice questions should I solve to prepare for WBJEE 2025 physical chemistry?

One should solve as many as possible practice questions to prepare for WBJEE 2025 physical chemistry.  
 

Where to get the WBJEE 2025 Physical Chemistry practice questions?

WBJEE 2025 Physical Chemistry practice questions are available online, check the article above to get important physical chemistry practice questions. 
 

What is the weightage of Physical Chemistry in WBJEE 2025?

The weightage of physical chemistry in the WBJEE exam is around 8%
 

What topics are there in the Physical Chemistry section for WBJEE 2025?

Atomic Structure, Radioactivity and Nuclear Chemistry, and Thermodynamics are some of the important topics in the WBJEE 2025 physical chemistry exam. 
 

Should I practice Physical Chemistry practice questions?

Yes, practicing questions is a great way to prepare for the WBJEE physical chemistry. 
 

How many questions are asked from the Physical Chemistry section in WBJEE 2025?

Physical Chemistry topics may cover 4-7 questions in the WBJEE exam.
 

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