KURMA SANSKRITI INSTITUTE OF PHARMACEUTICAL SCIENCE,JEHANABAD B.Ed fees is 60,000 INR (Yearly). KURMA SANSKRITI INSTITUTE OF PHARMACEUTICAL SCIENCE,JEHANABAD B.Ed admission 2024 will be based on CUET.
Course | Duration | Fees |
Bachelor of Education (B.Ed.) | 2 Years | 60000 INR |
B.Ed in Special Education (Education) | 2 Years | 60000 INR |
To pursue a B.Ed. (Bachelor of Education) degree at Kurma Sanskriti Institute of Pharmaceutical Science, Jehanabad, candidates must fulfill certain eligibility criteria. Applicants should have completed their undergraduate degree in any discipline from a recognized university with a minimum aggregate of 50%. Additionally, they should have studied Education as a subject in their undergraduate program or should have completed a postgraduate degree in Education. It is also essential for candidates to have obtained a valid score in the entrance examination conducted by the institute or any other recognized authority. Meeting these eligibility requirements will enable aspiring individuals to embark on a rewarding journey in the field of education at Kurma Sanskriti Institute of Pharmaceutical Science, Jehanabad.
Admission to the B.Ed at KURMA SANSKRITI INSTITUTE OF PHARMACEUTICAL SCIENCE,JEHANABAD is subject to meeting the eligibility criteria and the candidates have to secure a valid score in CUET. All shortlisted candidates have to complete the KURMA SANSKRITI INSTITUTE OF PHARMACEUTICAL SCIENCE,JEHANABAD B.Ed admission process by getting their documents verified and paying the admission fee.
KURMA SANSKRITI INSTITUTE OF PHARMACEUTICAL SCIENCE,JEHANABAD B.Ed application form has to be submitted online by visiting the official website. Candidates aspiring to take admission to the B.Ed course at KURMA SANSKRITI INSTITUTE OF PHARMACEUTICAL SCIENCE,JEHANABAD have to first check and meet the eligibility criteria and then proceed further with the application process.