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MHT CET Chemistry Previous Year Question Papers: PDF Download

As MHT CET is approaching, practicing the MHT CET Chemistry Previous Year Question Papers will be beneficial for the candidates. Candidates can download the year and shift-wise MHT CET Chemistry Question Paper PDF for free.

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Practicing MHT CET Chemistry Previous Year Question Papers can help candidates gain insight into the exam pattern, the types of questions asked in the exam, marking scheme. Another advantage of practicing the previous year's MHT CET question papers for chemistry is it helps in building time management skills which is an important ingredient in succeeding a state-level exam like MHT CET. While practicing MHT CET Chemistry PYQ, candidates will be able to find out certain aspects like the repetitive questions, their strengths, and weaknesses upon which they can work.  

As per CollegeDekho experts, to succeed MHT CET Chemistry exam, candidates are required to pay more attention to the formula-based questions, periodic table, and organic chemistry. In this article, candidates will be able to check download the MHT CET Chemistry Previous year question papers PDF free.

Also Check - List of Topics to Score 40+ in MHT CET Chemistry

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MHT CET 2017 Chemistry Question Paper PDF

MHT CET 2016 Chemistry Question Paper 

Why Practice MHT CET Chemistry Previous Years Question Papers?

Practicing the previous year's MHT CET questions of the Chemistry section will shield the preparation strategy of the candidate. The advantages of practicing the MHT CET Chemistry PYQ have been explained below.
  • Candidates can figure out their strengths and weaknesses in the MHT CET Chemistry syllabus, upon which they will be able to work more to reach the level of accuracy. 
  • Practicing these papers helps the candidate to understand the question paper pattern, marking scheme, and overall structure.
  • Most importantly, candidates will be able to learn time management skills. This is the crucial aspect in exams where the number of attempts is more compared to the duration.
  • PYQ helps in building the accuracy of the candidate.
  • Questions repeat in the exam. Practicing the MHT CET PYQ of chemistry will make it easier for the candidates to identify them.

Also Check, 

How to Solve MHT CET Chemistry Previous Years Question Papers?

Aspirants preparing for MHT CET should practice the previous year's question papers in the same format as the exam. As the duration of the exam is 180 minutes, candidates should make sure that they allocate their time wisely. 
  • Go through the paper once and check the questions that you will be able to answer.
  • Mark the questions for later that you are unsure of or might be able to solve later.
  • Initially focus on the question that you are 100% sure of. 
  • Do not invest much time into 1 question. If you are not able to solve a question, do not sit idle and think. Shift to the next question. 

Also Check, 

MHT CET Chemistry Sample Questions

A. Which of the following pair of compounds demonstrates the law of multiple proportions?
  1. CH4, CCl4
  2. BF3, NH3
  3. CO, CO2
  4. NO2, CO2
Explanation - This option correctly represents the law of multiple proportions. Both consist of carbon and oxygen. In carbon monoxide, one atom of carbon combines with one atom of oxygen, whereas in carbon dioxide, one atom of carbon combines with two atoms of oxygen. Here, the fixed mass of carbon combines with varying masses of oxygen in a ratio of 1:2 (for the oxygen atoms).

B. Calculate the percent atom economy when a product of formula weight 175u is obtained in a chemical reaction using 225u formula weight reactant.
  1. 70.1%
  2. 77.7%
  3. 90.5%
  4. 95.0%
Explanation - Atom Economy= (Molecular weight of the desired product/Total molecular weight of reactants)×100%

In the given question, we have a product with a formula weight of 175u which is obtained from a reactant with a formula weight of 225u. Using the formula :

  • Atom Economy= (175u/225u)×100%
  • Atom Economy= (175/225)×100%
  • Atom Economy= 0.7777...×100% 
  • Atom Economy= 77.77...%

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