KURMA SANSKRITI INSTITUTE OF PHARMACEUTICAL SCIENCE,JEHANABAD BA+B.Ed fees is 40,000 INR (Yearly). KURMA SANSKRITI INSTITUTE OF PHARMACEUTICAL SCIENCE,JEHANABAD BA+B.Ed admission 2024 will be based on CUET.
Course | Duration | Fees |
B.A. B.Ed. | 4 Years | 40000 INR |
To be eligible for the B.A. + B.Ed. degree program at Kurma Sanskriti Institute of Pharmaceutical Science, Jehanabad, candidates must meet certain criteria. Firstly, applicants should have completed their higher secondary education (10+2) or an equivalent examination from a recognized board. They should have pursued their studies in any stream, including Science, Commerce, or Arts. Additionally, candidates must have secured a minimum aggregate score of 50% in their qualifying examination. Furthermore, it is important for applicants to clear any entrance examinations or interviews conducted by the institute to gain admission to the B.A. + B.Ed. program. Meeting these eligibility criteria will ensure consideration for admission into this esteemed institute.
Admission to the BA+B.Ed at KURMA SANSKRITI INSTITUTE OF PHARMACEUTICAL SCIENCE,JEHANABAD is subject to meeting the eligibility criteria and the candidates have to secure a valid score in CUET. All shortlisted candidates have to complete the KURMA SANSKRITI INSTITUTE OF PHARMACEUTICAL SCIENCE,JEHANABAD BA+B.Ed admission process by getting their documents verified and paying the admission fee.
KURMA SANSKRITI INSTITUTE OF PHARMACEUTICAL SCIENCE,JEHANABAD BA+B.Ed application form has to be submitted online by visiting the official website. Candidates aspiring to take admission to the BA+B.Ed course at KURMA SANSKRITI INSTITUTE OF PHARMACEUTICAL SCIENCE,JEHANABAD have to first check and meet the eligibility criteria and then proceed further with the application process.