KURMA SANSKRITI INSTITUTE OF PHARMACEUTICAL SCIENCE,JEHANABAD B.Sc+B.Ed fees is 40,000 INR (Yearly). KURMA SANSKRITI INSTITUTE OF PHARMACEUTICAL SCIENCE,JEHANABAD B.Sc+B.Ed admission 2024 will be based on CBSE 12th, UP 12th.
Course | Duration | Fees |
B.Sc. + B.Ed. | 4 Years | 40000 INR |
To be eligible for the B.Sc. + B.Ed. degree program at Kurma Sanskriti Institute of Pharmaceutical Science, Jehanabad, candidates must meet certain criteria. Firstly, applicants should have passed the 10+2 examination or its equivalent from a recognized board with a minimum aggregate of 50% in the science stream. Additionally, they should have studied Physics, Chemistry, and Biology as compulsory subjects. Furthermore, candidates must have a valid score in the relevant entrance examination conducted by the institute or any other recognized authority. Meeting these eligibility requirements will enable students to pursue the B.Sc. + B.Ed. degree and gain comprehensive knowledge in the field of pharmaceutical sciences.
Admission to the B.Sc+B.Ed at KURMA SANSKRITI INSTITUTE OF PHARMACEUTICAL SCIENCE,JEHANABAD is subject to meeting the eligibility criteria and the candidates have to secure a valid score in CBSE 12th, UP 12th. All shortlisted candidates have to complete the KURMA SANSKRITI INSTITUTE OF PHARMACEUTICAL SCIENCE,JEHANABAD B.Sc+B.Ed admission process by getting their documents verified and paying the admission fee.
KURMA SANSKRITI INSTITUTE OF PHARMACEUTICAL SCIENCE,JEHANABAD B.Sc+B.Ed application form has to be submitted online by visiting the official website. Candidates aspiring to take admission to the B.Sc+B.Ed course at KURMA SANSKRITI INSTITUTE OF PHARMACEUTICAL SCIENCE,JEHANABAD have to first check and meet the eligibility criteria and then proceed further with the application process.