Sandip University BTech cutoff 2024 is 45% marks in Class 12 from a recognised board. Candidates must have physics/ mathematics/ chemistry/ computer science/ electronics/ information technology/ biology/ informatics practices/ biotechnology/ technical vocational subject/ agriculture/ engineering graphics/ business studies/ entrepreneurship in Class 12. Sandip University cutoff 2024 for BTech (Lateral Entry) is also 45% at the diploma (10+3) level exam.
Exam | Cut off Percentage |
Class 12 | 45% with physics/ mathematics/ chemistry/ computer science/ electronics/ information technology/ biology/ informatics practices/ biotechnology/ technical vocational subject/ agriculture/ engineering graphics/ business studies/ entrepreneurship |
Diploma | 45% marks in aggregate |
Sandip University cutoff 2024 for the BDes programme is 50% aggregate marks at 10+2 level. Students with class 12 scores from a recognised board of education are eligible for admission. Further, Sandip University BDes cutoff 2024 is also passing the 10th Diploma in any stream from any board of education. However, the diploma shall be from a board recognised by the Central/State Government. As Sandip University cut-off is not officially announced, applicants can check the qualifying cut-off marks tabulated below.
Class 12 | Passed (10+2) or equivalent course in any discipline from a recognized Board/ Council/ University with a minimum of 50% marks for the general (open) category and 45% marks for the reserved category. |
Class 10th Diploma | Passed 10th Diploma in any stream from any recognised board of education. |
Sandip University BTech + MBA Cutoff 2024 is 50% marks in class 12 from a recognised board of education. Additionally, students shall have valid JEE Main/MHT CET scores for admission to BTech + MBA integrated programme. Further, candidates having a Diploma in Engineering are also eligible to apply for this programme. As Sandip University BTech + MBA cutoff is not released officially, students can check the qualifying cutoff below to understand the eligibility for admissions.
Particulars | Details |
12th | 50% aggregate marks in class 12 from the science stream with mathematics as a mandatory subject + MHT CET/JEE Main scores. Prior work experience in the management or engineering field will be advantageous. |
10+3 Diploma | Diploma in Engineering |
The cutoff required for admission to B.Pharm at Sandip University is 45% in the qualifying examination. Studnets meeting the required cutoff will be shortlisted for the final merit list.
B.Tech cutoff for admission to Sandip University is 45% marks in the qualifying examination. Final selection is done based on the marks obtained in JEE Main/MHT-CET or SU-JEE.
The cutoff percentage for Sandip University varies from course to course. For example, 45% minimum marks are required in qualifying exams for admission to B.Tech, BSc, BBA, B.Com, etc. On the other hand, 50% minimum marks are required for M.Tech, MCA and MBA admission at Sandip University.
Sandip University hasnt disclosed the JEE Main cutoff required for admission to the BTech course. However, a candidate must secure at least 45% marks in the qualifying exam to be eligible to apply for the B.Tech programme.
Sandip University cut off 2024 has been released for all the courses. Studnets willing to apply for admissions must meet the course-specific minimum marks. They must know that the Sandip University cut off percentile is qualifying in nature and final selection is based on merit. The cut-off percentage varies from course to course. For example, Sandip University MBA cutoff is 50% marks in graduation whereas the cut-off percentage for BBA is 45% in Class 12.
Every year, Sandip University releases qualifying cut-offs for admission to its engineering courses such as B.Tech and M.Tech. Sandip University cutoff for BTech programmes is 45% marks in Class 12. Students meeting this requirement can apply for their desired engineering courses at the UG level. However, the final selection will be based on the valid marks obtained in the entrance examination such as JEE Mains/MHT CET or SU JEE. However, Sandip University cut off for JEE Mains and other tests has not been disclosed by the university. Moreover, the minimum percentage required for application to Sandip University M.Tech course is 50% in Graduation.
Sandip University has released the cut-off for OBC category to apply for different courses such as LLB, LLM, M.SC and PhD. Sandip University OBC cut off for the LLB (Hons.) and BA/BBA LLB is 42% marks in bachelor's degree and Class 12 respectively. OBC cutoff for the LLM programme is 50% and for the M.Sc programme is 45% at the graduation level. At the doctoral level, the sandip university cut off for PhD programme is 50% for OBC candidates belonging to the non-creamy layer.
Sandip University has not disclosed the JEE Main cut off required for admission to the B.Tech programme. However, students applying to B.Tech courses must have a valid score in JEE Main for the final selection. Moreover, the minimum qualification to apply for B.Tech at Sandip University is 45% in Class 12.
Students willing to apply for the LLM programme at Sandip University must have taken GATE or equivalent tests such as SUN PG/SLAT PG and obtained a valid score. However, the university hasn’t disclosed the GATE cutoff based on which the final selection is done. Apart from this, a student has to score at least 55% marks at graduation level. This is the qualifying cutoff to apply for the LLM programme at Sandip University.
No, Sandip University does not release cut off marks for its entrance tests. The university conducts various entrance examinations such as SU-JEE, SU-MAT, SU-LAT, SU-DAT, SUNPET, etc for admission to different courses. It selects students based on their performance in qualifying as well as entrance exams. However, it doesn’t disclose its final cut off for its entrance exams publicly.