AP EAMCET Probability Weightage 2025

AP EAMCET Probability Weightage 2025 is expected to be 3.75% in the Mathematics section. This chapter holds 3 to 4 marks in the AP EAMCET Mathematics section. These marks can make a significant difference in the overall ranking, as AP EAMCET is highly competitive. The Probability chapter in the AP EAMCET exam covers fundamental concepts such as basic probability concepts, Conditional Probability, Bayes' Theorem, Permutations and Combinations, Independent and Dependent Events, Random Variables and Distributions, and Binomial Probability Distribution. These topics equip students with essential problem-solving skills for analyzing events, calculating probabilities, and understanding probability distributions in various scenarios. In this article, you will be able to understand the AP EAMCET Probability Weightage 2025 along with its concepts that will help you to prepare well for the exam.

Direct Link: AP EAMCET 2025 Application Form (Activated)

Latest Update: AP EAMCET 2025 Application Form has been live. Students can fill and submit the application form without a late fee untill April 24, 2025. According to the official schedule, AP EAPCET 2025 Agriculture & Pharmacy exam will be held on May 19 and 20, 2025 and the AP EAMCET 2025 Engineering exam will be conducted from May 21 to 27, 2025 .

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Expected AP EAMCET Probability Weightage 2025

Candidates who are planning to appear for AP EAMCET 2025 must note that the expected AP EAMCET 2025 Probability Weightage is 3.75% of the Mathematics total score. Test takers can expect around 3 to 4 questions from this chapter. Students are advised to master all the topics in the AP EAMCET Probability chapter.

Check Also: AP EAMCET Syllabus 2025

AP EAMCET Probability Weightage of Previous Years

Here’s a table showing the year-wise weightage of the Probability chapter in AP EAMCET from 2019 to 2024.

The Probability chapter has consistently held a weightage of around 3.75% in the AP EAMCET exam from 2019 to 2024.

Important Topics of AP EAMCET 2025 Probability and Weightage

Here’s a table outlining the important Probability topics for AP EAMCET 2025, along with their expected weightage:

Sample Probability Questions for AP EAMCET 2025

Here are some sample questions to illustrate the type of Probability problems you might encounter in AP EAMCET:

Question 1:

A bag contains 4 red balls, 3 blue balls, and 5 green balls. If two balls are drawn randomly, what is the probability that both balls are red?

• Solution: Total number of balls = 4 + 3 + 5 = 12 Probability of drawing two red balls: P(two red balls)=(42)(122)=666=111P(\text{two red balls}) = \frac{\binom{4}{2}}{\binom{12}{2}} = \frac{6}{66} = \frac{1}{11}P(two red balls)=(212​)(24​)​=666​=111​

Question 2:

A die is thrown twice. What is the probability that the sum of the numbers rolled is 8?

• Solution: Total possible outcomes = 6 × 6 = 36 Favorable outcomes: (2,6), (3,5), (4,4), (5,3), (6,2) = 5 outcomes. Probability: P(sum is 8)=536P(\text{sum is 8}) = \frac{5}{36}P(sum is 8)=365​

Question 3:

What is the probability of getting at least one head when three coins are tossed?

• Solution: Total outcomes = 23=82^3 = 823=8 (HHH, HHT, HTH, HTT, THH, THT, TTH, TTT) Probability of no head = 1 outcome (TTT). Probability of at least one head = 1−18=781 - \frac{1}{8} = \frac{7}{8}1−81​=87​.

Question 4:

What is the probability of getting exactly two heads when three coins are tossed?

• Solution: Total outcomes = 23=82^3 = 823=8. Outcomes with exactly two heads are (HHT, HTH, and THH), so there are 3 favourable outcomes.
  Probability = 38\frac{3}{8}83​.

Question 5:

A die is rolled. What is the probability of rolling a number greater than 4?

• Solution: Possible outcomes greater than 4 are 5 and 6, so there are 2 favorable outcomes out of 6.
  Probability = 26=13\frac{2}{6} = \frac{1}{3}62​=31​.

Question 6:

A bag contains 5 red balls and 3 blue balls. If one ball is drawn at random, what is the probability it is red?

• Solution: Total balls = 5 + 3 = 8. Favorable outcomes (red) = 5.
  Probability = 58\frac{5}{8}85​.

Question 7:

Two dice are rolled together. What is the probability that the sum of the numbers is 7?

• Solution: Possible outcomes for a sum of 7 are (1,6), (2,5), (3,4), (4,3), (5,2), (6,1), totalling 6 favourable outcomes out of 36.
  Probability = 636=16\frac{6}{36} = \frac{1}{6}366​=61​.

In conclusion, Probability is a high-scoring and important topic in the Mathematics section of AP EAMCET 2025. With an approximate weightage of  3.75%, mastering this topic can significantly boost your overall score. By focusing on understanding the fundamental concepts, practising regularly, and revising frequently, you can ensure that you are well-prepared for the Probability questions in AP EAMCET 2025.

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