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KCET Physics All Formulas PDF - KCET 2024 Physics is one of the most important sections. As per the previous year's analysis, the KCET Physics section consists of formula-based questions. As per the information brochure, the KCET Physics Syllabus is divided into two parts - First and Second PUC syllabi as directed by the Department of Pre-University Education of Karnataka State. To score 160+ in KCET, candidates should focus on the KCET formulas to improve their preparation strategy.
KCET 2024
has been revised and will be conducted from April 18 and 19, 2024, and April 20 for the Kannada language. Before the exam, candidates are advised to check the KCET Physics All Formulas PDF from this article to ace their KCET 2024 preparation.
LATEST -
KCET Admit Card 2024 Released
KCET Physics All Formulas PDF
Candidates preparing for KCET Physics should download and learn the KCET Physics Formula thoroughly before the exam. The table below consists of the KCET Physics formula sets.KCET Physics Formula PDF - Set 1 | KCET Physics Formula PDF - Set 2 |
---|---|
KCET Physics Formula PDF - Set 3 | KCET Physics Formula PDF - Set 4 |
KCET Physics Formula PDF - Set 5 |
Source - TestPrep Cart
KCET Physics Syllabus 2024
The table below highlights the syllabus of KCET Physics 2024.
PUC Syllabus for KCET 2024 | PUC Syllabus for KCET 2024 |
---|---|
|
|
KCET 2024 Physics - Topic Wise Weightage
Some of the topics holding the highest weight in KCET Physics are Gravitation, Magnetism Matter, etc. Candidates can check the topic-wise weightage of KCET 2024 Physics.
KCET 2024 First PUC Important Topics
The table below shows the KCET Physics important topics from the first PUC.
Chapters | Weightage |
---|---|
Gravitation | 8 |
Oscillations | 7 |
Motion in a straight line | |
Thermodynamics | |
Mechanical properties of fluids | 4 |
Mechanical properties of solids | |
Kinetic theory | |
Units and measurement | 3 |
Physical world | 2 |
KCET 2024 Second PUC Important Topics
The table below shows the KCET Physics important topics from the second PUC.
Chapters | Weightage |
---|---|
Magnetism and Matter | 7 |
Alternating Current | |
Electromagnetic Induction | 6 |
Nuclei | |
Atoms | 5 |
Communication Systems | 3 |
Electromagnetic Waves | 2 |
KCET Physics - Most Asked Questions from Previous Year Question Papers
Candidates can check the KCET physics questions below.
- A moving coil galvanometer is converted into an ammeter of range 0 to 5mA. The galvanometer resistance is 90Ω and the shunt resistance has a value of 10Ω. If there are 50 divisions in the galvanometer-turned ammeter on either side of zero, its current sensitivity is -
- 1 × 105 A/div
- 2 × 104 A/div
- 1 × 105 div/A
- 2 × 104 div/A
B. The energy gap of an LED is 2.4 eV. When the LED is switched ‘ON’, the momentum of the emitted photons is
- 2.56 × 10-27 kg.m.s-1
- 1.28 × 10-11 kg.m.s-1
- 0.64 × 10-27 kg.m.s-1
- 1.28 × 10-27 kg.m.s-1
C. If the length of a conductor is increased by 20% and the cross-sectional area is decreased by 4%, then calculate the percentage change in the resistance of the conductor.
Answer- 25%
D. A cell of emf 90V is connected across a series combination of two resistors each of 100Ω resistance A voltmeter of resistance 400Ω is used to measure the potential difference across each resistor The reading of the voltmeter will be :
- 45V
- 40V
- 80V
- 90V
E. A hollow cylindrical conductor has a length of 314m, while its inner and outer diameters are 4mm and 8mm respectively The resistance of the conductor is n × 10 −3 Ω n × 10 −3 Ω. If the resistivity of the material is 24 × 10 − 8 Ω 24 × 10 −8 Ω m The value of n is ___.
SOLUTION -
R=ρ A ℓ, the cross-sectional area is π(b2−a2)
R=ρ π (b2−a2) ℓ=3.14×(42−22)×10−62.4×10−8×3.14
=2×10−3Ω
∴ n=2
F. A metallic rod of length 1 m held along the east-west direction is allowed to fall freely. Given the horizontal component of earth’s magnetic field BH = 3 × 10-5 T. The emf induced in the rod at an instant t = 2s after it is released is (Take g = 10 ms-2 )
- 3 × 10-3 V
- 3 × 10-4 V
- 6 × 10-3 V
- 6 × 10-4 V
G. The energy gap of an LED is 2.4 eV. When the LED is switched ‘ON’, the momentum of the emitted photons is -
- 2.56 × 10-27 kg.m.s-1
- 1.28 × 10-11 kg.m.s-1
- 0.64 × 10-27 kg.m.s-1
- 1.28 × 10-27 kg.m.s-1
H. In Young’s double-slit experiment, the intensity of light passing through each of the two double slits is 2 × 10-2 Wm-2. The screen-slit distance is very large in comparison with the slit-slit distance. The fringe width is β. The distance between the central maximum and a point P on the screen is 33 β. Then the total light intensity at that point is -
- 4 × 10-2 Wm-2
- 2 × 10-2 Wm-2
- 16 × 10-2 Wm-2
- 8 × 10-2 Wm-2
I. If the area of cross-section is halved and the length of a wire having Young's modulus Y is doubled, then its new Young's modulus will be -
- Y
- 4Y
- Y/2
- Y/4
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