20+ XAT 2025 Arithmetic Questions with Answers

The XAT 2025 Arithmetic questions will cover topics such as percentages, ratios & proportions, profit and loss, speed and distance, and averages. Arithmetic is a key area in the XAT 2025 QA & DI syllabus, with around 9-11 questions expected from this section. Arithmetic and Algebra make up 54% of the total weightage, while Modern Math and Number Systems play a major role, contributing 32% to the quantitative section. With the XAT 2025 exam scheduled for January 5, 2025, practicing solved arithmetic questions will enhance your numerical simplification skills, equipping you to handle more challenging problems in the XAT 2025 exam . Now is the perfect time to start solving arithmetic problems.

Also Read:

XAT 2025 Topic Wise Arithmetic Questions with Solutions

The XAT 2025 aspirants must solve the XAT Arithmetic Questions to acquaint themselves with the question types. Solving XAT 2025 Arithmetic Questions will help you to know your strong and weak areas.

XAT Profit Loss & Discount Questions

The section below has some XAT Profit Loss & Discount Questions and the Important Formulas you require to solve these questions.

Important XAT Profit Loss & Discount Formulas

1. Profit % = Profit/(C P)×100
2. Profit/Gain = (S.P.) – (C.P.)
3. C P = 100/(100+gain %)×S P
4. S P = (100+gain % )/100 ×C P
5. Loss % = Loss/(C.P.)×100
6. Loss = (C.P.) – (S.P.)
7. C P = 100/(100-loss %)×S P
8. S P = (100-loss %)/100×C P

Question : A shopkeeper sells groceries using weights that are 15% less than the true weights and manages to make a profit of 20%. What is his total gain percentage?

Answer : 41.17%

Solution : Let's assume the weight of a grocery bag to be 1 kg. The actual weight, considering the 15% reduction, is 85% of 1000 grams, which equals 850 grams. If we consider the cost price of each gram to be Re. 1, then the cost price of each bag is Rs. 850. The selling price of 1 kg of bag is 120% of the true cost price. Therefore, SP = 120/100 x 1000 = Rs. 1200. The gain is calculated as the difference between the selling price and the cost price: Gain = 1200 - 850 = Rs. 350. Hence, the gain percentage is calculated as (350/850) x 100 = 41.17%.

Question : A man bought some toys at the rate of 10 for Rs. 40 and sold them at 8 for Rs. 35. What is his gain or loss percentage?

Answer : 9.375%

Solution : The cost price of 10 toys is Rs. 40, so the cost price of 1 toy is Rs. 4.
The selling price of 8 toys is Rs. 35, which means the selling price of 1 toy is Rs. 35/8.
The gain is calculated as the difference between the selling price and the cost price of 1 toy: Gain = (35/8) - 4 = 3/8. Hence, the gain percentage is calculated as [(3/8)/4] x 100 = 9.375%.

Question : A customer wanted to purchase an item marked for ₹10000. Shopkeepers offered two types of discounts, 25% flat discount or successive discounts of 14% and 12%. Which is the better offer for the customers and by how much?

1. first offer by ₹68
2. second offer by ₹68
3. first offer by ₹32
4. second offer by ₹100

Answer : A

Solution : 25% flat discount
The selling price of the item = 75100×10000 = ₹7500
Successive discounts of 14% and 12%
The price of the item after a 14% discount = 86100 × 10000  = ₹8600
Price of the item after 12% discount = 88100 × 8600 = ₹7568
Difference between selling prices = 7568 – 7500 = ₹68
The first offer is better at ₹68.
Hence, the correct answer is Option A

Question : Hari suffered a loss of 8% by selling an article. If he had sold it for ₹300 more, he would have made a profit of 4%. Find his CP (in ₹).

a) 2400
b) 2250
c) 2575
d) 2500

Answer : 2500

Solution : Let the cost price of the article = 100C
Hari suffered a loss of 8% by selling an article.
The selling price of the article =  92100 × 100C = 92C
If he had sold it for ₹300 more, he would have made a profit of 4%.
92C + 300 = 104100 × 100C
92C + 300 = 104C
12C = 300
C = 25
The cost price of the article = ₹2500
Hence, the correct answer is Option D

XAT Speed & Distance Questions

Important XAT Speed, Time, and Distance Formulas:

1. Speed= Distance/ Time
2. Distance= Speed x Time
3. Time= Distance/ Time

Question : At its usual speed, a train of length L metres crosses a platform 300 metres long in 25 seconds. The train crosses a vertical pole at 50% of its usual speed in 20 seconds. What is the value of L?

a) 140

b) 200

c) 400

d) 320

e) 350

Answer :  B

Question : A 260-meter-long train crosses a 120-meter-long wall in 19 seconds. What is the speed of the train?

a) 77 km/hr

b) 69 km/hr

c) 62 km/hr

d) 72 km/hr

Answer : D

Question : A train at 120 kmph crosses a signal in 15 seconds. What is the length of the train in meters?

a) 200

b) 100

c) 500

d) Cannot determined

Answer: C

Question : Mr. X decides to travel from Delhi to Gurgaon at a uniform speed and decides to reach Gurgaon after T hr. After 30 km, there is some engine malfunction and the speed of the car becomes (4/5)th of the original speed. So, he travels the rest of the distance at a constant speed (4/5)th of the original speed and reaches Gurgaon 45 minutes late. Had the same thing happened after he travelled 48 km, he would have reached only 36 minutes late. What is the distance between Delhi and Gurgaon?

1. 90 km
2. 120 km
3. 20 km
4. 40 km

Answer : B

XAT Time & Work Questions

The section below has some XAT Time & Work Questions and the Important Formulas you require to solve these questions.

Important XAT Time & Work Formulas:

1. If X can do a piece of work in ‘n’ days, then X’s 1 day’s work = 1/n
2. If X’s 1 day’s work = is 1/n, then X can finish the work in n days.

Question : It takes six technicians a total of 10 hr to build a new server from Direct Computer, with each working at the same rate. If six technicians start to build the server at 11 am, and one technician per hour is added beginning at 5 pm, at what time will the server be completed?

a) 6.40 pm

b) 7 pm

c) 7.20 pm

d) 8 pm

Answer : D

Solution :

Let the work done by each technician in one hour be 1 unit.
Therefore, total work to be done = 60 units.
From 11 AM to 5 PM, work done = 6*6 = 36 units.
Work remaining = 60 – 36 = 24 units.
Work done in the next 3 hours = 7 units + 8 units + 9 units = 24 units.
Therefore, the work gets done by 8 PM.

Question : Two boats, travelling at 5 and 10 km per hour, head directly towards each other. They begin at a distance of 20 km from each other. How far apart are they (in km) one minute before they collide?

a) 1/12

b) 1/6

c) 1/4

d) 1/3

Answer : C

Solution : The relative speed is 15 km/hr = 15 km/60 min = 0.25 km/min = 250 m/min.
Therefore, one minute before they collide, they are at a distance of 250m.

XAT Percentage Questions

The section below has some XAT Percentage Questions and the Important Formulas you require to solve these questions.

Important XAT Percentage Formulas:

1. Find what percentage of X is Y: Y/X x 100
2. Increase N by S% = N(1+S/100)
3. Decrease N by S% = N(1 - S/100)

Question : A woman earns ₹ 1,000/day. After some weeks, she earns ₹1,160/day. By how much percentage did her earnings
increase?

a) 18%

b) 16%

c) 17%

d) 15%

Answer : B

Solution :

Increase in earnings of the woman = 1160 – 1000 = ₹ 160/day
Therefore, Percentage increase in earnings of the woman = 160
1000 ×100 = 16%

Question : The average of some numbers is 54.6. If 75% of the numbers are increased by 5.6 each, and the rest are decreased by 8.4 each, then what is the average of the numbers so obtained?

a) 55.6

b) 55.8

c) 56.7

d) 56.3

Answer : C

Solution :

New average of the numbers = (average + increment/decrements)
The average of some numbers = 54.6
75% of the numbers increased by 5.6 each, and the rest are decreased by 8.4 each so,
New average of the numbers = 54.6 + (5.6 \times 75/100 – 8.4 \times 25/100) = 54.6 + 4.2 – 2.1 = 56.7.

XAT 2025 Arithmetic Syllabus

In the Quantitative Aptitude syllabus, Arithmetic asks the maximum number of questions. Check the table below for key topics of XAT Arthematic Syllabus 2025.

Practise these questions well and remember the XAT Quantitative Ability section can be quite a scoring portion of the exam if you prepare for it effectively. Good Luck!

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