JEE Main Daily Practice Questions 2 January 2025

Prasanthi Boodati

Updated On: January 02, 2025 06:30 AM

To enhance the regular preparation for JEE Main Session 1 2025, aspirants should solve practice questions daily. Here are JEE Main Daily Practice Questions 2 January 2025 for Physics, Chemistry, and Mathematics.


 
JEE Main Daily Practice Questions 2 January 2025JEE Main Daily Practice Questions 2 January 2025

JEE Main Daily Practice Questions 2 January 2025: JEE Main Session 1 2025 will take place from January 22 to 31. Applicants preparing for the exam must focus on practising the JEE Main sample papers. Hence, here are some daily practice questions with answers for JEE Main 2 January  2025, including five questions from each subject: Mathematics, Physics, and Chemistry.

Also Read | NEET Daily Practice Questions 2 January 2025

JEE Main Daily Practice Questions 2 January 2025: Physics

Candidates can check out the JEE Main daily practice questions 2 January 2025 from the Physics section:

Question 1: A body is projected vertically upwards from the surface of earth with a velocity equal to one third of escape velocity. The maximum height attained by the body will be:

(Take radius of earth = 6400 km and g = 10 ms–2)

(A) 800 km

(B) 1600 km

(C) 2133 km

(D) 4800 km

Answer (A)

Question 2: The oscillating magnetic field in a plane electromagnetic wave is given by By = 5 × 10–6 sin1000p(5x – 4 × 108t)T.

The amplitude of electric field will be:

(A) 15 × 102 Vm–1

(B) 5 × 10–6 Vm–1

(C) 16 × 1012Vm–1

(D) 4 × 102Vm–1

Answer (D)

Question 3: The maximum and minimum voltage of an amplitude modulated signal are 60 V and 20 V respectively. The percentage modulation index will be:

(A) 0.5%

(B) 50%

(C) 2%

(D) 30%

Answer (B)

Question 4: A nucleus of mass M at rest splits into two parts having masses M '/3 and 2M /3' (M ' < M ) . The ratio of de Broglie wavelength of two parts will be:

(A) 1 : 2

(B) 2 : 1

(C) 1 : 1

(D) 2 : 3

Answer (C)

Question 5: An ice cube of dimensions 60 cm × 50 cm × 20 cm is placed in an insulation box of wall thickness 1 cm. The box keeping the ice cube at 0°C of temperature is brought to a room of temperature 40°C. The rate of melting of ice is approximately.

(Latent heat of fusion of ice is 3.4 × 105 J kg–1 and thermal conducting of insulation wall is 0.05 Wm–1°C–1)

(A) 61 × 10–3 kg s–1

(B) 61 × 10–5 kg s–1

(C) 208 kg s–1

(D) 30 × 10–5 kg s–1

Answer (B)

JEE Main Daily Practice Questions 2 January 2025: Chemistry

Candidates can check out the JEE Main daily practice questions 2 January 2025 from the Chemistry section:

Question 1: Given below are two statements: one is labelled as Assertion A and other is labelled as Reason R.

Assertion A : Finest gold is red in colour, as the size of the particles increases, it appears purple then blue and finally gold.

Reason R : The colour of the colloidal solution depends on the wavelength of light scattered by the dispersed particles.

In the light of the above statements, choose the most appropriate answer from the options given below.

(A) Both A and R are true and R is the correct explanation of A

(B) Both A and R are true but R is NOT the correct explanation of A

(C) A is true but R is false

(D) A is false but R is true

Answer (A)

Question 2: The metal that is not extracted from its sulfide ore is

(A) Aluminium

(B) Iron

(C) Lead

(D) Zinc

Answer (A)

Question 3: The products obtained from a reaction of hydrogen peroxide and acidified potassium permanganate are

(A)  Mn4+, H2O only

(B)  Mn2+, H2O only

(C) Mn4+, H2O, O2 only

(D) Mn2+, H2O, O2 only

Answer (D)

Question 4: Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.

Assertion A : LiF is sparingly soluble in water.

Reason R : The ionic radius of Li+ ion is smallest among its group members, hence has least hydration enthalpy.

In the light of the above statements, choose the most appropriate answer from the options given below.

(A) Both A and R are true and R is the correct explanation of A

(B) Both A and R are true but R is NOT the correct explanation of A

(C) A is true but R is false.

(D) A is false but R is true.

Answer (C)

Question 5: Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.

Assertion A: Boric acid is a weak acid

Reason R: Boric acid is not able to release H+ ion on its own. It receives OH– ions from water and releases H+ ion.

In the light of the above statements, choose the most appropriate answer from the options given below.

(A) Both A and R are correct and R is the correct explanation of A.

(B) Both A and R are correct but R is NOT the correct explanation of A

(C) A is correct but R is not correct

(D) A is not correct but R is correct

Answer (B)

JEE Main Daily Practice Questions 2 January 2025: Mathematics

Candidates can check out the JEE Main daily practice questions 2 January 2025 from the Maths section:

Problem 1: Let p and q be two positive numbers such that p + q = 2 and p4 + q4 = 272. Then p and q are roots of the equation :

(1) x2 – 2x + 2 = 0

(2) x2 – 2x + 8 = 0

(3) x2 – 2x + 136 = 0

(4) x2 – 2x + 16 = 0

Solution (4)

Problem 2: The system of linear equations

3x – 2y –   kz = 10

2x – 4y – 2z = 6

x + 2y – z = 5m

is inconsistent if :

(1) k is not equal to 3, m is not equal to 4/5

(2) k is not equal to 3

(3) k is equal to 3, m is equal to 4/5

(4) k is equal to 3, m is not equal to 4/5

Solution (4)

Problem 3: A scientific committee is to be formed from 6 Indians and 8 foreigners, which includes at least 2 Indians and double the number of foreigners as Indians. Then the number of ways, the committee can be formed, is :

(1) 560

(2) 1050

(3) 1625

(4) 575

Solution (3)

Problem 4: The equation of the plane passing through the point (1, 2, –3) and perpendicular to the planes 3x + y – 2z = 5 and 2x – 5y – z = 7, is:

(1) 3x – 10y – 2z + 11 = 0

(2) 6x – 5y – 2z – 2 = 0

(3) 6x – 5y + 2z + 10 = 0

(4) 11x + y + 17z + 38 = 0

Solution (4)

Problem 5: An ordinary dice is rolled a certain number of times. If the probability of getting an odd number 2 times is equal to the probability of getting an even number 3 times, then the probability of getting an odd number for odd number of times is :

(1) 3/16

(2) 1/2

(3) 1/32

(4) 5/16

Solution (2)

Also Read |
JEE Main DPP 31 December 2024: Daily practice problems for 2025 aspirants
NEET Daily Practice Questions 31 December 2024: DPP for 2025 aspirants

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