Dear student,
Would love to understand how and why would want an answer to this question!! The total number of 5 digit numbers is 90000.
Here's the break-up of how we arrived at this result:
To find the total number of 5-digit numbers, we need to determine the range of these numbers.
The smallest 5-digit number is 10000. The largest 5-digit number is 99999.
To find the total count of numbers within this range (inclusive), we can use the formula: Total numbers = (Largest number - Smallest number) + 1
Total 5-digit numbers = (99999 - 10000) + 1 Total 5-digit numbers = 89999 + 1 Total 5-digit numbers = 90000
Alternatively, we can think of it in terms of the number of choices for each digit:
A 5-digit number can be represented as _ _ _ _ _.
~For the first digit (the ten thousands place), it cannot be 0, so there are 9 possible choices (1 to 9).
~For the second digit (the thousands place), there are 10 possible choices (0 to 9).
~For the third digit (the hundreds place), there are 10 possible choices (0 to 9).
~For the fourth digit (the tens place), there are 10 possible choices (0 to 9).
~For the fifth digit (the units place), there are 10 possible choices (0 to 9).
The total number of 5-digit numbers is the product of the number of choices for each digit: Total 5-digit numbers = 9 × 10 × 10 × 10 × 10 = 9 × 10^4 = 9 × 10000 = 90000
The final answer is 90000
Nmms bihar ka result kab aayega 2025 me aaj to 1 June hai may to samapt ho gaya hai
How many passing marks in the exam
i want H booklet question paper of 2025