CAT Sequence & Series Practice Questions With Solutions

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CAT Quant Sequence & Series Practice Questions

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Question 1.

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Let both the series a1,a2,a3a_{1},a_{2},a_{3}... and b1,b2,b3b_{1},b_{2},b_{3}... be in arithmetic progression such that the common differences of both the series are prime numbers. If a5=b9,a19=b19a_{5}=b_{9},a_{19}=b_{19} and b2=0b_{2}=0, then a11a_{11} equals

Question 2.

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If x is a positive real number such that x8+(1x)8=47x^8 + \left(\frac{1}{x}\right)^8 = 47, then the value of x9+(1x)9x^9 + \left(\frac{1}{x}\right)^9 is

Question 3.

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For a real number x, if 12,log3(2x9)log34\frac{1}{2}, \frac{\log_3(2^x - 9)}{\log_3 4}, and log5(2x+172)log54\frac{\log_5\left(2^x + \frac{17}{2}\right)}{\log_5 4} are in an arithmetic progression, then the common difference is

Question 4.

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The value of 1+(1+13)14+(1+13+19)116+(1+13+19+127)164+1 + \left(1 + \frac{1}{3}\right)\frac{1}{4} + \left(1 + \frac{1}{3} + \frac{1}{9}\right)\frac{1}{16} + \left(1 + \frac{1}{3} + \frac{1}{9} + \frac{1}{27}\right)\frac{1}{64} + ------- is

Question 5.

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Let an=46+8na_n = 46 + 8n and bn=98+4nb_n = 98 + 4n be two sequences for natural numbers n100n \leq 100. Then, the sum of all terms common to both the sequences is

Question 6.

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For any natural number n, suppose the sum of the first n terms of an arithmetic progression is (n+2n2)(n + 2n^2). If the nthn^{th} term of the progression is divisible by 9, then the smallest possible value of n is

Question 7.

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Consider the arithmetic progression 3, 7, 11, ... and let AnA_n denote the sum of the first n terms of this progression. Then the value of 125n=125An\frac{1}{25} \sum_{n=1}^{25} A_{n} is

Question 8.

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If x0=1,x1=2x_0 = 1, x_1 = 2, and xn+2=1+xn+1xn,n=0,1,2,3,......,x_{n + 2} = \frac{1 + x_{n + 1}}{x_n}, n = 0, 1, 2, 3, ......, then x2021x_{2021} is equal to

Question 9.

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Three positive integers x, y and z are in arithmetic progression. If yx>2y-x>2 and xyz=5(x+y+z)xyz=5(x+y+z), then z-x equals

Question 10.

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For a sequence of real numbers x1,x2,...xnx_{1},x_{2},...x_{n}, If x1x2+x3....+(1)n+1xn=n2+2nx_{1}-x_{2}+x_{3}-....+(-1)^{n+1}x_{n}=n^{2}+2n for all natural numbers n, then the sum x49+x50x_{49}+x_{50} equals

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Question 1.

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Consider a sequence of real numbers, x1,x2,x3,...x_{1},x_{2},x_{3},... such that xn+1=xn+n1x_{n+1}=x_{n}+n-1 for all n1n\geq1. If x1=1x_{1}=-1 then x100x_{100} is equal to

Question 2.

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Let the m-th and n-th terms of a geometric progression be 34\frac{3}{4} and 12. respectively, where m<nm < n. If the common ratio of the progression is an integer r, then the smallest possible value of r+nmr + n - m is

Question 3.

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If x1=1x_1=-1 and xm=xm+1+(m+1)x_m=x_{m+1}+(m+1) for every positive integer m, then X100X_{100} equals

Question 4.

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If a1,a2,......a_1, a_2, ...... are in A.P., then, 1a1+a2+1a2+a3+.......+1an+an+1\frac{1}{\sqrt{a_1} + \sqrt{a_2}} + \frac{1}{\sqrt{a_2} + \sqrt{a_3}} + ....... + \frac{1}{\sqrt{a_n} + \sqrt{a_{n + 1}}} is equal to

Question 5.

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Let a1,a2,...a_1, a_2, ... be integers such that
a1a2+a3a4+....+(1)n1an=n,a_1 - a_2 + a_3 - a_4 + .... + (-1)^{n - 1} a_n = n, for all n1.n \geq 1.
Then a51+a52+....+a1023a_{51} + a_{52} + .... + a_{1023} equals

Question 6.

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The number of common terms in the two sequences: 15, 19, 23, 27, . . . . , 415 and 14, 19, 24, 29, . . . , 464 is

Question 7.

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Let x, y, z be three positive real numbers in a geometric progression such that x < y < z. If 5x, 16y, and 12z are in an arithmetic progression then the common ratio of the geometric progression is

Question 8.

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If the square of the 7th term of an arithmetic progression with positive common difference equals the product of the 3rd and 17th terms, then the ratio of the first term to the common difference is

Question 9.

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Let a1a_1, a2a_2,.............,  a3na_{3n} be an arithmetic progression with a1a_1 = 3 and a2a_{2} = 7. If a1a_1+ a2a_{2} +...+ a3na_{3n}= 1830, then what is the smallest positive integer m such that m(a1a_1+ a2a_{2} +...+ ana_n) > 1830?

Question 10.

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If a1=12×5,a2=15×8,a3=18×11,...,a_{1}=\frac{1}{2\times5},a_{2}=\frac{1}{5\times8},a_{3}=\frac{1}{8\times11},..., then a1+a2+a3+...+a100a_{1}+a_{2}+a_{3}+...+a_{100} is

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