MHT CET Previous Year Question Papers with Solutions and Answer Keys PDF

Updated By Dewesh Nandan Prasad on 18 Apr, 2025 11:31

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MHT CET Previous Years Question Papers are available here free of cost. Download the MHT CET question paper PDF for previous years from this page. MHT CET Previous year papers will help candidates to understand the difficulty level of questions, subject-wise weightage of topics, type of questions, and other important aspects of the exam.

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MHT CET Previous Year Question Papers

MHT CET Previous Year Question Paper is available here in the form of PDFs. Candidates preparing for the MHT CET exam 2025 must go through the MHT CET previous year question papers to ensure the best preparation for the MHT CET exam. The previous year's question papers will provide the candidates with insights into the exam, like the exam pattern, important topics, weightage of topics, important questions, etc. Practising the MHT CET previous years question papers PCM will help the students enhance their time management skills and accuracy in solving the questions. 

JEE Question Papers will also help aspiring candidates to know the detailed MHT CET 2025 Exam Pattern and other aspects of the questions, like specific topics that are important in the exam. MHT CET question paper PDFs become crucial as they are a very important part of the MHT CET 2025 preparation. Candidates are also advised to go through the MHT CET preparation tips along with the question papers, as they will help them develop a good strategy for the exam. Check the MHT CET 2025 question paper PDF for download on the page below.

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Sample MHT CET 2025 Question Paper

If you are an aspirant of MHT CET 2025 Exam, candidates can check and practice the MHT CET 2025 Question Paper PDF below:

MHT CET Previous Years Question Papers: Free Download

Candidates can download the MHT CET Previous Year Question Paper PDF from the table below. To download the MHT CET Previous Year Papers, candidates have to merely click the question paper link, and the PDF will be available for download:

How to Download the MHT CET Previous Year Question Papers?

The CET Cell Maharashtra does not release the MHT CET question papers separately; the registered candidates can only download the response sheet that will contain the questions asked in the MHT CET exam. Check the steps to download the MHT CET previous year's question papers/response sheet below:

  • Go to the official website 

  • Click on the MHT CET provisional answer key link 

  • Log in to the registered account 

  • The response sheet/question paper will appear on the screen 

  • Download the MHT CET previous years question papers PCM and save them for later use

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How To Solve MH CET Previous Year Papers?

The purpose of solving the previous year papers of MHT CET is to improve the overall test-taking strategy used by the candidates. As candidates solve MHT CET previous year papers, their level of accuracy increases enabling them to finish the paper on time.

  1. Allocate two separate time slots of 90 minutes each for the two papers of MHT CET.
  2. Begin with your strong subject (for Paper 2). If Mathematics is your strongest subject, start with it.
  3. Carefully go through all the questions as they appear and try to understand whether or not you will be able to solve them.
  4. Attempt only those questions that you are 100% sure about. Skip the rest.
  5. For questions that you are not fully sure about but you think you should give a shot, mark them.
  6. Once you have gone through the entire paper and answered all the questions that you are sure about, try to attempt the marked questions. Then try the next level of questions, and so on.
  7. Do not spend too much time on any question, nor answer any question in a hurry.

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MHT CET 2025: Important Topics

Candidates preparing from the MHT CET previous year's question paper PDF must check the subject-wise important topics, which are repeated almost every year.  Check the important topics for the MHT CET 2025 exam in the table below:

Subject

Important Topics

Mathematics
  • Trigonometric Functions

  • Sets, Relations & Functions

  • Permutations and Combination

  • Relations & Functions

  • Principle of Mathematical Induction

  • Complex numbers and Quadratic equations Linear Inequalities

Physics

  • Physical World

  • Units and Measurements, Laws of Motion

  • Work, Energy & Power

  • Motion in a Straight Line, Plane

  • Mechanical Properties of Solids and Fluids

  • Systems of Particles and Rotational Motion Gravitation

Chemistry

  • Classification of Elements and Periodicity in Properties

  • Redox reactions

  • Equilibrium, Structure of Atom

  • Basic Concepts of Chemistry

  • Chemical Bonding

  • Molecular Structure States

Advantages of Solving MHT CET Previous Years’ Question Papers

Mentioned below are some of the advantages of solving MHT CET previous years’ question papers/sample paper:

  • With the help of MHT CET previous years’ question papers/sample paper, candidates can get an idea of the MHT CET exam pattern, type and nature of questions that are asked in the entrance exam, and candidates will also be able to practice the different type of questions

  • By taking MHT CET previous years’ question papers/sample paper, candidates can improve their question-solving ability, speed, and time-management skills

  • Through solving MHT CET previous year papers with solutions, candidates can analyze their strong and weak areas

  • Candidates preparing for the exam can use the MHT CET old question papers as a reference to know the MHT CET previous year papers marking scheme of each section and questions

  • Most importantly solving MHT CET sample papers and previous years’ question papers give the candidates the feel of solving the actual exam and are the only source of quality practice which is required to face the exams

MHT CET Practice Questions For PCM & PCB

Practice MHT CET 2025 PCM and PCB practice questions from the following questions.

Physics

Question 1:

A body is projected vertically upwards with a velocity of 20 m/s. The maximum height reached by the body is:

(a) 10 m (b) 20 m (c) 30 m (d) 40 m

Solution:

We can use the following equation of motion to solve this problem:

v^2 = u^2 + 2as

where:

  • v = final velocity (0 m/s at the maximum height)
  • u = initial velocity (20 m/s)
  • a = acceleration due to gravity (-10 m/s^2)
  • s = displacement (maximum height)

Substituting the values, we get:

0 = (20)^2 + 2(-10)s 0 = 400 - 20s 20s = 400 s = 20 m

Therefore, the correct answer is (b) 20 m.


Question 2:

Two wires of the same material have lengths in the ratio 1:2 and radii in the ratio 2:1. The ratio of their resistances is:

(a) 1:2 (b) 2:1 (c) 1:8 (d) 8:1

Solution:

The resistance of a wire is given by the formula:

R = ρl/A

where:

  • R = resistance
  • ρ = resistivity of the material
  • l = length of the wire
  • A = cross-sectional area of the wire

Let the lengths of the two wires be l1 and l2, and their radii be r1 and r2, respectively. Then, the ratio of their resistances is:

R1/R2 = (ρl1/πr1^2) / (ρl2/πr2^2) R1/R2 = (l1/l2) * (r2^2/r1^2)

Substituting the given ratios, we get:

R1/R2 = (1/2) * (2^2/1^2) R1/R2 = 2

Therefore, the correct answer is (b) 2:1.


Question 3:

A particle is moving in a circle of radius 1 m with a speed of 2 m/s. The centripetal acceleration of the particle is:

(a) 2 m/s^2 (b) 4 m/s^2 (c) 8 m/s^2 (d) 16 m/s^2

Solution:

The centripetal acceleration of a particle moving in a circle is given by the formula:

a = v^2/r

where:

  • a = centripetal acceleration
  • v = speed of the particle
  • r = radius of the circle

Substituting the given values, we get:

a = (2)^2/1 a = 4 m/s^2

Therefore, the correct answer is (b) 4 m/s^2.


Question 4:

A convex lens has a focal length of 10 cm. An object is placed at a distance of 20 cm from the lens. The image distance is:

(a) 10 cm (b) 20 cm (c) 30 cm (d) 40 cm

Solution:

We can use the lens formula to solve this problem:

1/f = 1/v + 1/u

where:

  • f = focal length (10 cm)
  • v = image distance
  • u = object distance (-20 cm)

Substituting the values, we get:

1/10 = 1/v + 1/(-20) 1/10 = 1/v - 1/20 1/v = 1/10 + 1/20 1/v = 3/20 v = 20/3 cm

Therefore, the correct answer is (a) 10 cm.


Question 5:

A body of mass 1 kg is moving with a velocity of 10 m/s. The kinetic energy of the body is:

(a) 50 J (b) 100 J (c) 150 J (d) 200 J

Solution:

The kinetic energy of a body is given by the formula:

KE = (1/2)mv^2

where:

  • KE = kinetic energy
  • m = mass of the body
  • v = velocity of the body

Substituting the given values, we get:

KE = (1/2)(1)(10)^2 KE = 50 J

Therefore, the correct answer is (a) 50 J.


Chemistry

Question 1:

Which of the following is the correct IUPAC name for the compound CH3CH(OH)CH2CH3?

(a) 2-methylpropan-2-ol (b) 2-butanol (c) 3-butanol (d) 2-methylbutan-2-ol

Solution:

The longest carbon chain contains four carbon atoms, so the parent chain is butane. The hydroxyl group (OH) is attached to the second carbon atom, so the suffix is "-2-ol". There is also a methyl group (CH3) attached to the second carbon atom. Therefore, the correct IUPAC name is 2-methylbutan-2-ol.

Answer: (d) 2-methyl butane-2-ol


Question 2:

What is the major product formed when ethene reacts with HBr?

(a) Bromoethane (b) Ethylene dibromide (c) Bromoethene (d) Ethanol

Solution:

Ethene (CH2=CH2) reacts with HBr in an electrophilic addition reaction. The hydrogen atom of HBr adds to one carbon atom of the double bond, and the bromine atom adds to the other carbon atom. This results in the formation of bromoethane (CH3CH2Br).

Answer: (a) Bromoethane


Question 3:

Which of the following is the strongest acid?

(a) HCl (b) HBr (c) HI (d) HF

Solution:

The acidity of hydrohalic acids increases down the group in the periodic table. This is because the bond strength between hydrogen and the halogen atom decreases, making it easier for the hydrogen ion to be released. Therefore, HI is the strongest acid among the given options.

Answer: (c) HI


Question 4:

What is the oxidation state of sulfur in H2SO4?

(a) +2 (b) +4 (c) +6 (d) +8

Solution:

In H2SO4, the oxidation state of hydrogen is +1 and the oxidation state of oxygen is -2. Let the oxidation state of sulfur be x. Then, the overall charge of the molecule can be represented as:

2(+1) + x + 4(-2) = 0 2 + x - 8 = 0 x = +6

Answer: (c) +6


Question 5:

Which of the following is a colligative property?

(a) Boiling point (b) Freezing point (c) Osmotic pressure (d) All of the above

Solution:

Colligative properties are properties of solutions that depend on the number of solute particles present in the solution, but not on the nature of the solute particles. Boiling point elevation, freezing point depression, and osmotic pressure are all colligative properties.

Answer: (d) All of the above


Question 6:

What is the pH of a solution with a hydrogen ion concentration of 1 x 10^-5 M?

(a) 5 (b) 9 (c) 10 (d) 14

Solution:

The pH of a solution is defined as the negative logarithm of the hydrogen ion concentration:

pH = -log[H+]

In this case, [H+] = 1 x 10^-5 M, so:

pH = -log(1 x 10^-5) = 5

Answer: (a) 5


Question 7:

Which of the following elements has the highest electronegativity?

(a) Fluorine (b) Chlorine (c) Bromine (d) Iodine

Solution:

Electronegativity is the ability of an atom to attract electrons in a chemical bond. Electronegativity increases across a period and decreases down a group in the periodic table. Fluorine is the most electronegative element.

Answer: (a) Fluorine


Question 8:

What is the formula for calculating the molar mass of a compound?

(a) Sum of the atomic masses of all the atoms in the compound (b) Product of the atomic masses of all the atoms in the compound (c) Ratio of the atomic masses of all the atoms in the compound (d) Difference of the atomic masses of all the atoms in the compound

Solution:

The molar mass of a compound is the sum of the atomic masses of all the atoms in the compound.

Answer: (a) Sum of the atomic masses of all the atoms in the compound


Question 9:

Which of the following is an example of a condensation polymer?

(a) Polyethylene (b) Polypropylene (c) Nylon (d) PVC

Solution:

Condensation polymers are formed by the joining of monomers with the elimination of a small molecule, such as water. Nylon is an example of a condensation polymer, formed from the reaction of a diamine and a dicarboxylic acid.

Answer: (c) Nylon


Question 10:

What is the name of the process by which a solid changes directly into a gas?

(a) Melting (b) Boiling (c) Sublimation (d) Condensation

Solution:

Sublimation is the process by which a solid changes directly into a gas without passing through the liquid phase.

Answer: (c) Sublimation


Mathematics

Question 1:

If A = [[1, 2], [3, 4]] and B = [[5, 6], [7, 8]], then A + B is:

(a) [[6, 8], [10, 12]] (b) [[-4, -4], [-4, -4]] (c) [[1, 7], [10, 12]] (d) [[6, 7], [8, 9]]

Solution:

Matrix addition is performed element-wise. So, A + B = [[1+5, 2+6], [3+7, 4+8]] = [[6, 8], [10, 12]]

Answer: (a) [[6, 8], [10, 12]]


Question 2:

The value of the determinant |[2, 3], [4, 5]| is:

(a) -2 (b) 2 (c) 8 (d) 22

Solution:

The determinant of a 2x2 matrix [[a, b], [c, d]] is ad - bc. So, |[2, 3], [4, 5]| = (25) - (34) = 10 - 12 = -2

Answer: (a) -2


Question 3:

If f(x) = x^2 + 2x + 1, then f(2) is:

(a) 5 (b) 9 (c) 10 (d) 11

Solution:

Substitute x = 2 into the function: f(2) = (2)^2 + 2(2) + 1 = 4 + 4 + 1 = 9

Answer: (b) 9


Question 4:

The slope of the line 2x + 3y = 6 is:

(a) 2/3 (b) -2/3 (c) 3/2 (d) -3/2

Solution:

Rewrite the equation in slope-intercept form (y = mx + b), where m is the slope. 3y = -2x + 6 => y = (-2/3)x + 2. Therefore, the slope is -2/3.

Answer: (b) -2/3


Question 5:

The integral of x^2 is:

(a) x^3 + C (b) (x^3)/3 + C (c) 2x + C (d) x^2 + C

Solution:

The power rule of integration states that the integral of x^n is (x^(n+1))/(n+1) + C. So, the integral of x^2 is (x^3)/3 + C.

Answer: (b) (x^3)/3 + C


Question 6:

The derivative of sin(x) is:

(a) cos(x) (b) -cos(x) (c) tan(x) (d) cot(x)

Solution:

The derivative of sin(x) is cos(x).

Answer: (a) cos(x)


Question 7:

The equation of a circle with centre (2, -3) and radius 4 is:

(a) (x-2)^2 + (y+3)^2 = 4 (b) (x+2)^2 + (y-3)^2 = 4 (c) (x-2)^2 + (y+3)^2 = 16 (d) (x+2)^2 + (y-3)^2 = 16

Solution:

The equation of a circle with centre (h, k) and radius r is (x-h)^2 + (y-k)^2 = r^2. So, the equation is (x-2)^2 + (y+3)^2 = 4^2 = 16.

Answer: (c) (x-2)^2 + (y+3)^2 = 16


Question 8:

The value of sin(π/2) is:

(a) 0 (b) 1 (c) -1 (d) √2/2

Solution:

sin(π/2) = 1

Answer: (b) 1


Question 9:

If tan(θ) = 3/4, then cos(θ) is:

(a) 3/5 (b) 4/5 (c) 5/3 (d) 5/4

Solution:

Since tan(θ) = opposite/adjacent = 3/4, we can consider a right triangle with opposite side 3 and adjacent side 4. The hypotenuse is √(3^2 + 4^2) = 5. cos(θ) = adjacent/hypotenuse = 4/5.

Answer: (b) 4/5


Question 10:

The limit of (sin(x)/x) as x approaches 0 is:

(a) 0 (b) 1 (c) ∞ (d) -∞

Solution:

This is a standard limit: lim (x->0) sin(x)/x = 1

Answer: (b) 1


Biology

Question 1:

Which of the following is NOT a characteristic of all living organisms?

(a) Reproduction (b) Metabolism (c) Movement (d) Consciousness

Solution:

While most living organisms exhibit movement, it's not a universal characteristic. For example, plants are living organisms but generally don't exhibit locomotion in the same way animals do. Reproduction, metabolism, and consciousness (responsiveness to stimuli) are considered fundamental characteristics of life.

Answer: (c) Movement


Question 2:

The primary site of photosynthesis in plants is:

(a) Roots (b) Stems (c) Leaves (d) Flowers

Solution:

Leaves contain chloroplasts, which are the organelles where photosynthesis takes place. Their large surface area and arrangement maximize light absorption.

Answer: (c) Leaves


Question 3:

Which of the following is the most inclusive (broadest) taxonomic category?

(a) Genus (b) Species (c) Kingdom (d) Family

Solution:

The taxonomic hierarchy proceeds from broadest to most specific: Kingdom, Phylum, Class, Order, Family, Genus, Species.

Answer: (c) Kingdom


Question 4:

Which of these is a vestigial structure in humans?

(a) Heart (b) Appendix (c) Brain (d) Lungs

Solution:

A vestigial structure has lost its original function during evolution. The appendix is considered a vestigial organ in humans.

Answer: (b) Appendix


Question 5:

The process of meiosis results in:

(a) Two identical daughter cells (b) Four genetically different daughter cells (c) Two genetically different daughter cells (d) Four identical daughter cells

Solution:

Meiosis is a type of cell division that reduces the number of chromosomes by half and produces gametes (sex cells). It results in four genetically different haploid daughter cells.

Answer: (b) Four genetically different daughter cells


Question 6:

Which gas is most abundant in Earth's atmosphere?

(a) Oxygen (b) Carbon Dioxide (c) Nitrogen (d) Hydrogen

Solution:

Nitrogen makes up approximately 78% of Earth's atmosphere.

Answer: (c) Nitrogen


Question 7:

Which of the following is a DNA base NOT found in RNA?

(a) Adenine (b) Guanine (c) Cytosine (d) Thymine

Solution:

Thymine is replaced by Uracil in RNA.

Answer: (d) Thymine


Question 8:

The basic structural and functional unit of life is:

(a) Tissue (b) Organ (c) Cell (d) Organ System

Solution:

The cell is the fundamental unit of life. All living organisms are composed of cells.

Answer: (c) Cell


Question 9:

Which of the following is an example of a monosaccharide?

(a) Sucrose (b) Lactose (c) Glucose (d) Starch

Solution:

Glucose is a monosaccharide (a simple sugar). Sucrose and lactose are disaccharides, and starch is a polysaccharide.

Answer: (c) Glucose


Question 10:

Which of these is responsible for carrying oxygen in the blood?

(a) Hemoglobin (b) Plasma (c) Platelets (d) White blood cells

Solution:

Haemoglobin, a protein found in red blood cells, is responsible for transporting oxygen throughout the body.

Answer: (a) Hemoglobin

Want to know more about MHT-CET

FAQs about MHT-CET Question Papers

Why is it necessary to solve the MHT CET previous year's question papers

It is beneficial to solve the previous year's question papers for the preparation of the MHT CET exam, as solving the previous papers can help in understanding the exam pattern, weightage of topics in different sessions, and identifying the important topics in the exam. If the candidate will solve the previous year's question papers in exam conditions, then it will help with time management and accuracy.

 

What is the MHT CET exam pattern?

The exam pattern of the MHT CET exam is divided into two sections that are Physics and Chemistry (Section 1) and Mathematics/Biology (Section 2). The exam will be conducted for a duration of 3 hours (180 minutes) for a total of 100 questions (50 questions per section).

 

What is the MHT CET exam pattern?

The exam pattern of the MHT CET exam is divided into two sections that are Physics and Chemistry (Section 1) and Mathematics/Biology (Section 2). The exam will be conducted for a duration of 3 hours (180 minutes) for a total of 100 questions (50 questions per section).

 

Is there any negative marking on the MHT CET exam?

No, there is no negative marking in the MHT CET exam. However, the candidates are advised to practice for accuracy as it will be a good practice for other exams as well.

 

What is the eligibility to appear for the MHT CET exam?

The minimum eligibility to appear for the MHT CET exam is to possess a 10+2 degree with at least 45% marks, however, for the reserved category, it is 40%. There are no age limit criteria or number of attempts  to appear for the exam

In how many languages is the MHT CET exam conducted?

The MHT CET exam is conducted in three languages Marathi, Urdu, and English. Candidates appearing for the exam can use any of the following languages to read and answer the questions. Also, the languages can be switched by the candidate at any point of the exam using the language button available on the screen.

 

What is the MHT CET Biology Syllabus 2025?

MHT CET syllabus for Biology is prescribed by the Maharashtra Common Entrance TET State Cell. The Syllabus for the MHT CET exam remains almost same every year. Candidates can check the syllabus for the MHT CET biology syllabus below:

i) Biomolecules

ii) Respiration & Energy Transfer

iv) Human Nutrition

v) Excretion

vi) Osmoregulation

 

What is the MHT CET Maths Syllabus 2025?

MHT CET maths syllabus is divided into topics like trigonometry, straight lines, probability, etc. Check the complete syllabus of the MHT CET Maths exam below:

i) Trigonometry 

ii) Straight line

iii) Circle

iv) Measures of Dispersion

v) Probability 

vi) Complex Numbers

vii) Permutations & Combinations

viii) Functions

ix)Limits

x) Continuit

What is the MHT CET Chemistry Syllabus?

MHT CET Chemistry syllabus is prescribed by the Government of Maharashtra Common Entrance Test Cell every year. The syllabus for the MHT CET chemistry remains almost same for every year. Check the MHT CET chemistry syllabus below:

i) Basic Concepts of Chemistry

ii) Structure of Atom

iii) Chemical Bonding

iv) Redox reactions

v) Elements of Groups 1 & 2

vi) States of Matter

vii) Adsorption & Colloids

viii) Surface Chemistry

ix) Hydrocarbons

x) Basic Principles of Organic Chemistry

 

What is the MHT CET Physics Syllabus 2025?

MHT CET Physics syllabus is based on the syllabus of Class 11 and 12. Students who are preparing for the MHT CET can check the syllabus for Physics below:

i) Motion in a plane

ii) Laws of Motion

iii) Gravitation

iv) Thermal properties of matter

v) Sound Optics

vi) Electrostatics

vii)) Semiconductors

 

Is it easy to score 150 in the MHT CET exam?

It  is not a mammoth task to secure a 150+ score in the MHT CET exam. All candidates need is to make a proper study plan and schedule their study. Moreover, 80% of the total questions asked will be from the class 12 syllabus only making it easier for the candidates as they will be able to remember more of the class 12 course.

Does questions get repeated from MHT CET previous year question papers?

Yes, sometimes questions from the MHT CET previous year papers PDF get repeated in the exam. 

When should I start attempting the MHT CET previous year papers?

Once you have been thorough with the syllabus of the exam, you can start attempting MHT CET previous year papers. 

From where can I get the MHT CET previous year papers?

CollegeDekho has provided the various MHT CET previous year question papers on this page. 

How is MHT CET previous year question paper helpful?

By attempting the MHT CET previous year question paper you will be able to evaluate your performance, improve time accuracy, work on your weak topics, and get the experience of real-time exam. 

Does the MHT CET previous year papers have same difficulty level as the MHT CET 2025 exam?

Yes, MHT CET previous year papers PDF have the same difficulty level as the real time MHT CET exam 2025. 

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