NIMCET Sample Papers with Solutions and Answer Keys PDF

NIMCET Sample Papers 2025

NIMCET 2025 Sample Papers is the exact replica of the actual NIMCET question paper. Candidates preparing for NIMCET are advised to practice the NIMCET 2025 Sample Papers so that they are able to understand the exam pattern, marking scheme, and question paper format. Along with all of these candidates can also master time management skills and increase their efficiency. Solving the sample papers for the upcoming NIMCET 2025 will help candidates get acquainted with the NIMCET 2025 syllabus. On the other hand, solving the sample papers will help candidates devise a strategy and create shortcut tricks while practising the NIMCET sample papers.

NIMCET Question paper is divided into four sections - Mathematics, Analytical Ability & Logical Reasoning, Computer Awareness and General English. As per the NIMCET marking scheme,  50 Questions are asked from Mathematics, 40 Questions from Analytical Ability & Logical Reasoning, 20 Questions from Computer Awareness, and 10 Questions from General English. Here, we have prepared a NIMCET 2025 Sample Papers with Solutions and Answer Keys PDF so that candidates can practice them before the exam. 

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NIMCET 2025 Sample Papers PDF With Solutions

Given below is the NIMCET 2025 Sample Papers PDF, test takers can practice sample questions by downloading it.

NIMCET 2025 Sample Questions Subject Wise

Check the NIMCET 2025 Subject Wise Sample Questions from the following -

NIMCET 2025 Sample Questions on Mathematics

1. Question: Find the derivative of f(x)=ln⁡(sin⁡(x))f(x) = \ln(\sin(x))f(x)=ln(sin(x)).
   Solution:
   f′(x)=1sin⁡(x)⋅cos⁡(x)=cot⁡(x)f'(x) = \frac{1}{\sin(x)} \cdot \cos(x) = \cot(x)f′(x)=sin(x)1​⋅cos(x)=cot(x).

2. Question: Solve 2x+1=82^{x+1} = 82x+1=8.
   Solution:
   Rewrite 888 as 232^323: 2x+1=232^{x+1} = 2^32x+1=23.
   Equating powers: x+1=3x+1 = 3x+1=3.
   x=2x = 2x=2.

3. Question: Find the sum of all integers from 111 to 100100100.
   Solution:
   Use S=n(n+1)2S = \frac{n(n+1)}{2}S=2n(n+1)​.
   S=100(100+1)2=5050S = \frac{100(100+1)}{2} = 5050S=2100(100+1)​=5050.

4. Question: Simplify (a+b)3−(a−b)3(a+b)^3 - (a-b)^3(a+b)3−(a−b)3.
   Solution:
   Expand: (a+b)3−(a−b)3=2(3a2b+3ab2)=6ab(a+b)(a+b)^3 - (a-b)^3 = 2(3a^2b + 3ab^2) = 6ab(a+b)(a+b)3−(a−b)3=2(3a2b+3ab2)=6ab(a+b).

5. Question: Solve xx+2+2x+3=1\frac{x}{x+2} + \frac{2}{x+3} = 1x+2x​+x+32​=1.
   Solution:
   Simplify: x(x+3)+2(x+2)(x+2)(x+3)=1\frac{x(x+3) + 2(x+2)}{(x+2)(x+3)} = 1(x+2)(x+3)x(x+3)+2(x+2)​=1.
   x2+5x+6=(x+2)(x+3)x^2 + 5x + 6 = (x+2)(x+3)x2+5x+6=(x+2)(x+3).
   Solve: x=0x = 0x=0.

NIMCET 2025 Sample Questions on Logical Reasoning

1. Question: Find the missing term in the sequence: 3,6,11,18,?3, 6, 11, 18, ?3,6,11,18,?.
   Solution:
   Differences: 6−3=36-3 = 36−3=3, 11−6=511-6 = 511−6=5, 18−11=718-11 = 718−11=7.
   Next difference: 999.
   Missing term: 18+9=2718 + 9 = 2718+9=27.

2. Question: A clock shows 3:15. What is the angle between the hour and minute hands?
   Solution:
   Angle between hands: ∣30H−112M∣|30H - \frac{11}{2}M|∣30H−211​M∣, where H=3,M=15H = 3, M = 15H=3,M=15.
   =∣30(3)−112(15)∣=∣90−82.5∣=7.5∘= |30(3) - \frac{11}{2}(15)| = |90 - 82.5| = 7.5^\circ=∣30(3)−211​(15)∣=∣90−82.5∣=7.5∘.

3. Question: In a race of 100 meters, A beats B by 10 meters. How much distance will A beat B in a 200-meter race?
   Solution:
   A covers 100 meters in the time B covers 90 meters.
   For 200 meters, B will cover (200×90)/100=180(200 \times 90) / 100 = 180(200×90)/100=180.
   Distance A beats B: 200−180=20200 - 180 = 20200−180=20 meters.

NIMCET 2025 Sample Questions on Analytical Ability

1. Question: Solve 3x−7<2x+53x - 7 < 2x + 53x−7<2x+5.
   Solution:
   Simplify: x<12x < 12x<12.

2. Question: If a train 150 m long passes a pole in 15 seconds, find its speed.
   Solution:
   Speed = DistanceTime=15015=10\frac{\text{Distance}}{\text{Time}} = \frac{150}{15} = 10TimeDistance​=15150​=10 m/s.

NIMCET 2025 Sample Questions on Computer Awareness

1. Question: What is the ASCII value of the letter 'A'?
   Solution:
   ASCII value: 656565.

2. Question: Convert (1010)2(1010)_2(1010)2​ to decimal.
   Solution:
   (1010)2=1×23+0×22+1×21+0×20=8+0+2+0=10(1010)_2 = 1 \times 2^3 + 0 \times 2^2 + 1 \times 2^1 + 0 \times 2^0 = 8 + 0 + 2 + 0 = 10(1010)2​=1×23+0×22+1×21+0×20=8+0+2+0=10.

3. Question: Which sorting algorithm has a worst-case time complexity of O(n2)O(n^2)O(n2)?
   Solution: Bubble Sort.

NIMCET 2025 Sample Questions on English

1. Question: Correct the sentence: "She has went to the market."
   Solution:
   Correct form: "She has gone to the market."

2. Question: Find the antonym of "Transparent".
   Solution: Opaque.

Benefits of Practicing NIMCET 2025 Sample Papers

Some of the benefits of Practicing NIMCET 2025 Sample Papers are stated below

• Getting accustomed to the NIMCET 2025 Question Pattern.
• Improve time management skills.
• Get a thorough understanding of the NIMCET exam pattern 2025.
• Evaluate the strengths and weaknesses of their NIMCET preparation 2025.