JEE Main Electrostatics Practice Questions With Solutions

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JEE Main Physics Electrostatics Practice Questions

Question 1.

Five charges $+ q, + 5 q, - 2 q, + 3 q$ and $- 4 q$ are situated as shown in the figure. The electric flux due to this configuration through the surface $S$ is :

JEE Main 2024 (Online) 9th April Evening Shift Physics - Electrostatics Question 15 English

\frac{q}{ϵ_{0}}

\frac{3 q}{ϵ_{0}}

\frac{5 q}{ϵ_{0}}

\frac{4 q}{ϵ_{0}}

Question 2.

Two charged conducting spheres of radii $a$ and $b$ are connected to each other by a conducting wire. The ratio of charges of the two spheres respectively is:

a b

\frac{b}{a}

\frac{a}{b}

\sqrt{a b}

Question 3.

Two identical conducting spheres P and S with charge Q on each, repel each other with a force $16 N$ . A third identical uncharged conducting sphere $R$ is successively brought in contact with the two spheres. The new force of repulsion between $P$ and $S$ is :

1 N

6 N

12 N

4 N

Question 4.

$σ$ is the uniform surface charge density of a thin spherical shell of radius R. The electric field at any point on the surface of the spherical shell is :

σ / ϵ_{o} R

σ / \in_{o}

σ / 2 ϵ_{o}

σ / 4 ϵ_{o}

Question 5.

The vehicles carrying inflammable fluids usually have metallic chains touching the ground:

To protect tyres from catching dirt from ground

It is a custom

To alert other vehicles

To conduct excess charge due to air friction to ground and prevent sparking

Question 6.

In hydrogen like system the ratio of coulombian force and gravitational force between an electron and a proton is in the order of :

10¹⁹

10³⁹

10²⁹

10³⁶

Question 7.

A charge $q$ is placed at the center of one of the surface of a cube. The flux linked with the cube is:

\frac{q}{2 ϵ_{0}}

Zero

\frac{q}{4 ϵ_{0}}

\frac{q}{8 ϵ_{0}}

Question 8.

An infinitely long positively charged straight thread has a linear charge density $λ {Cm}^{- 1}$ . An electron revolves along a circular path having axis along the length of the wire. The graph that correctly represents the variation of the kinetic energy of electron as a function of radius of circular path from the wire is :

JEE Main 2024 (Online) 4th April Morning Shift Physics - Electrostatics Question 11 English Option 1

JEE Main 2024 (Online) 4th April Morning Shift Physics - Electrostatics Question 11 English Option 2

JEE Main 2024 (Online) 4th April Morning Shift Physics - Electrostatics Question 11 English Option 3

JEE Main 2024 (Online) 4th April Morning Shift Physics - Electrostatics Question 11 English Option 4

Question 9.

C_{1}

and

C_{2}

are two hollow concentric cubes enclosing charges

2 Q

and

3 Q

respectively as shown in figure. The ratio of electric flux passing through

C_{1}

and

C_{2}

is :

JEE Main 2024 (Online) 1st February Evening Shift Physics - Electrostatics Question 32 English

3 : 2

5 : 2

2 : 5

2 : 3

Question 10.

Force between two point charges $q_{1}$ and $q_{2}$ placed in vacuum at ' $r$ ' cm apart is $F$ . Force between them when placed in a medium having dielectric constant $K = 5$ at ' $r / 5$ ' $cm$ apart will be:

5 F

25 F

F / 5

F / 25

Question 1.

Two charges $q$ and $3 q$ are separated by a distance ' $r$ ' in air. At a distance $x$ from charge $q$ , the resultant electric field is zero. The value of $x$ is :

\frac{r}{3 (1 + \sqrt{3})}

\frac{(1 + \sqrt{3})}{r}

\frac{r}{(1 + \sqrt{3})}

r (1 + \sqrt{3})

Question 2.

A particle of charge ' $- q$ ' and mass ' $m$ ' moves in a circle of radius ' $r$ ' around an infinitely long line charge of linear charge density ' $+ λ$ '. Then time period will be given as :

(Consider $k$ as Coulomb's constant)

T^{2} = \frac{4 π^{2} m}{2 k λ q} r^{3}

T = \frac{1}{2 π r} \sqrt{\frac{m}{2 k λ q}}

T = \frac{1}{2 π} \sqrt{\frac{2 k λ q}{m}}

T = 2 π r \sqrt{\frac{m}{2 k λ q}}

Question 3.

The electrostatic potential due to an electric dipole at a distance ' $r$ ' varies as :

\frac{1}{r^{3}}

\frac{1}{r}

\frac{1}{r^{2}}

Question 4.

An electric field is given by $(6 \hat{i} + 5 \hat{j} + 3 \hat{k}) N / C$ . The electric flux through a surface area $30 \hat{i} m^{2}$ lying in YZ-plane (in SI unit) is :

180

150

Question 5.

Two charges of $5 Q$ and $- 2 Q$ are situated at the points $(3 a, 0)$ and $(- 5 a, 0)$ respectively. The electric flux through a sphere of radius ' $4 a$ ' having center at origin is :

\frac{2 Q}{ε_{0}}

\frac{7 Q}{ε_{0}}

\frac{3 Q}{ε_{0}}

\frac{5 Q}{ε_{0}}

Question 6.

Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R).

Assertion (A) : Work done by electric field on moving a positive charge on an equipotential surface is always zero.

Reason (R) : Electric lines of forces are always perpendicular to equipotential surfaces.

In the light of the above statements, choose the most appropriate answer from the options given below :

Both (A) and (R) are correct and (R) is the correct explanation of (A)

(A) is correct but (R) is not correct

Both (A) and (R) are correct but (R) is not the correct explanation of (A)

(A) is not correct but (R) is correct

Question 7.

An electric charge $10^{- 6} μ C$ is placed at origin $(0, 0)$ $m$ of $X - Y$ co-ordinate system. Two points $P$ and $Q$ are situated at $(\sqrt{3}, \sqrt{3}) m$ and $(\sqrt{6}, 0) m$ respectively. The potential difference between the points $P$ and $Q$ will be :

\sqrt{3} V

\sqrt{6} V

0 V

3 V

Question 8.

The electric field due to a short electric dipole at a large distance

(r)

from center of dipole on the equatorial plane varies with distance as :

\frac{1}{r^{2}}

\frac{1}{r}

r

\frac{1}{r^{3}}

Question 9.

A $10 μ C$ charge is divided into two parts and placed at $1 cm$ distance so that the repulsive force between them is maximum. The charges of the two parts are:

9 μ C, 1 μ C

5 μ C, 5 μ C

8 μ C, 2 μ C

7 μ C, 3 μ C

Question 10.

Two charges each of magnitude $0.01 C$ and separated by a distance of $0.4 mm$ constitute an electric dipole. If the dipole is placed in an uniform electric field ' $\vec{E}$ ' of 10 dyne/C making $30^{\circ}$ angle with $\vec{E}$ , the magnitude of torque acting on dipole is:

4 \cdot 0 \times 10^{- 10} Nm

1.5 \times 10^{- 9} Nm

1.0 \times 10^{- 8} Nm

2.0 \times 10^{- 10} Nm

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JEE Main Electrostatics Practice Questions With Solutions

JEE Main Physics Electrostatics Practice Questions

Question 1.

Question 2.

Question 3.

Question 4.

Question 5.

Question 6.

Question 7.

Question 8.

Question 9.

Question 10.

Question 1.

Question 2.

Question 3.

Question 4.

Question 5.

Question 6.

Question 7.

Question 8.

Question 9.

Question 10.

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