JEE Main Wave Optics Practice Questions With Solutions

In a Young's double slits experiment, the ratio of amplitude of light coming from slits is $2:1$2 : 1. The ratio of the maximum to minimum intensity in the interference pattern is:

The ratio of intensities at two points $\mathrm{P}$P and $\mathrm{Q}$Q on the screen in a Young's double slit experiment where phase difference between two waves of same amplitude are $\pi /3$\pi / 3 and $\pi /2$\pi / 2, respectively are

The width of fringe is $2\mathrm{mm}$2 \textrm{ } mm on the screen in a double slits experiment for the light of wavelength of $400\mathrm{nm}$400 \textrm{ } nm. The width of the fringe for the light of wavelength 600 $\mathrm{nm}$nm will be:

'$n$n' polarizing sheets are arranged such that each makes an angle ${45}^{\circ }$45^{\circ} with the preceeding sheet. An unpolarized light of intensity I is incident into this arrangement. The output intensity is found to be $I/64$I / 64. The value of $n$n will be:

Two polaroide $\mathrm{A}$A and $\mathrm{B}$B are placed in such a way that the pass-axis of polaroids are perpendicular to each other. Now, another polaroid $\mathrm{C}$C is placed between $\mathrm{A}$A and $\mathrm{B}$B bisecting angle between them. If intensity of unpolarized light is ${\mathrm{I}}_0$I_{0} then intensity of transmitted light after passing through polaroid $\mathrm{B}$B will be:

In a Young's double slit experiment, two slits are illuminated with a light of wavelength $800\mathrm{nm}$800 \textrm{ } nm. The line joining $A_{1}P$A_{1} P is perpendicular to $A_1{A}_2$A_{1} A_{2} as shown in the figure. If the first minimum is detected at $P$P, the value of slits separation 'a' will be:

The distance of screen from slits D = 5 cm

In Young's double slits experiment, the position of 5${}^{\mathrm{th}}$^{th} bright fringe from the central maximum is 5 cm. The distance between slits and screen is 1 m and wavelength of used monochromatic light is 600 nm. The separation between the slits is :

Given below are two statements :

Statement I : If the Brewster's angle for the light propagating from air to glass is ${\theta }_{\mathrm{B}}$\theta_{B}, then the Brewster's angle for the light propagating from glass to air is $\frac{\pi }{2}-{\theta }_B$\frac{\pi}{2} - \theta_{B}

Statement II : The Brewster's angle for the light propagating from glass to air is ${\tan }^{-1}({\mu }_{\mathrm{g}})$tan^{- 1} \left(\right. \mu_{g} \left.\right) where ${\mu }_{\mathrm{g}}$\mu_{g} is the refractive index of glass.

In the light of the above statements, choose the correct answer from the options given below :

An unpolarised light beam of intensity $2I_0$2 I_{0} is passed through a polaroid P and then through another polaroid Q which is oriented in such a way that its passing axis makes an angle of ${30}^{\circ }$30^{\circ} relative to that of P. The intensity of the emergent light is