Updated By Lam Vijaykanth on 07 Jan, 2025 21:16
If the variance of the frequency distribution
| 2 | 1 | 1 | 1 | 1 | 1 |
is 160, then the value of
The frequency distribution of the age of students in a class of 40 students is given below.
| Age | 15 | 16 | 17 | 18 | 19 | 20 |
|---|---|---|---|---|---|---|
| No of Students | 5 | 8 | 5 | 12 |
If the mean deviation about the median is 1.25, then
The mean and standard deviation of 20 observations are found to be 10 and 2 , respectively. On rechecking, it was found that an observation by mistake was taken 8 instead of 12. The correct standard deviation is
Let
Let the mean and the variance of 6 observations
Let M denote the median of the following frequency distribution
| Class | 0 - 4 | 4 - 8 | 8 - 12 | 12 - 16 | 16 - 20 |
|---|---|---|---|---|---|
| Frequency | 3 | 9 | 10 | 8 | 6 |
Then 20M is equal to :
If the mean and variance of five observations are
Let the mean of 6 observations
Let sets A and B have 5 elements each. Let the mean of the elements in sets A and B be 5 and 8 respectively and the variance of the elements in sets A and B be 12 and 20 respectively. A new set C of 10 elements is formed by subtracting 3 from each element of
Let
| 0 | 1 | 2 | 3 | 4 | 5 | |
|---|---|---|---|---|---|---|
where
Let the mean and variance of 12 observations be
The mean and variance of a set of 15 numbers are 12 and 14 respectively. The mean and variance of another set of 15 numbers are 14 and
Let
The mean and variance of 5 observations are 5 and 8 respectively. If 3 observations are 1, 3, 5, then the sum of cubes of the remaining two observations is :
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